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=\(\frac{3}{4}-\frac{5}{2}-\frac{5}{3}+\left(\frac{-1}{8}\right)=\frac{18}{24}-\frac{60}{24}-\frac{40}{24}-\frac{3}{24}=\frac{-85}{24}\)
\(\frac{3}{4}-\left(\frac{5}{2}+\frac{5}{3}\right)+\left(\frac{-1}{2}\right)^3\)
\(=\frac{3}{4}-\frac{25}{6}+\frac{-1}{8}\)
\(=\frac{18-100-3}{24}\)
\(=\frac{-85}{24}\)
Tk mk nha!
a, (x-15):5+22=24
( x - 15 ) : 5 = 2
x-15 = 10
x = 25
Đặt \(B=1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}\)
\(=\left(1+\frac{1}{99}\right)+\left(\frac{1}{3}+\frac{1}{97}\right)+\left(\frac{1}{5}+\frac{1}{95}\right)+...+\left(\frac{1}{49}+\frac{1}{51}\right)\)
\(=\frac{100}{99}+\frac{100}{3\times97}+\frac{100}{5\times95}+...+\frac{100}{49\times51}\)
\(=100\left(\frac{1}{99}+\frac{1}{3\times97}+\frac{1}{5\times95}+...+\frac{1}{49\times51}\right)\)
Đặt \(C=\frac{1}{1\times99}+\frac{1}{3\times97}+\frac{1}{5\times95}+...+\frac{1}{97\times3}+\frac{1}{99\times1}\)
\(=2\left(\frac{1}{99}+\frac{1}{3\times97}+\frac{1}{5\times95}+...+\frac{1}{49\times51}\right)\)
\(A=\frac{B}{6}=\frac{100}{2}=50\)
Vậy \(A=50\)
\(4\frac{3}{4}+\left(-0,375\right)+\frac{1}{8}+\left(-1,20\right)+\left(-2,5\right)+\frac{31}{12}\)
\(=\frac{19}{4}+\frac{-3}{8}+\frac{1}{8}+\frac{-6}{5}+\frac{-5}{2}+\frac{31}{12}\)
\(=\frac{570}{120}+\frac{-45}{120}+\frac{15}{120}+\frac{-144}{120}+\frac{-300}{120}+\frac{310}{120}\)
\(=\frac{406}{120}=\frac{203}{60}\)
a) \(\left(-3\right)\cdot\left(-2\right)\cdot\left(-5\right)\cdot4=-120\)
bạn giải ra chi tiết lun được không ?