\(25.\left(x-1\right)^2-16.\left(x+y\right)^2\)

b) \(x^3+...">

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2 tháng 7 2017

a) \(25.\left(x-1\right)^2-16\left(x+y\right)^2\)

= \(\left(5x-5\right)^2-\left(4x+y\right)^2\)

= \(\left(5x-5-4x-y\right)\left(5x-5+4x+y\right)\)

= \(\left(x-y-5\right)\left(9x+y-5\right)\)

b) \(x^3+3x^2+3x+1-27z^3\)

= \(\left(x+1\right)^3-27z^3\)

= \(\left(x+1-3z\right)\left(x^2+x.3z+9z^2\right)\)

c) \(x^2-2xy+y^2-xz+yz\)

= \(\left(x-y\right)^2-z\left(x-y\right)\)

= \(\left(x-y\right)\left(x-y-z\right)\)

d) \(a^3x-ab+b-x\)

= \(x\left(a^3-1\right)-b\left(a-1\right)\)

= \(x\left(a-1\right)\left(a^2+a+1\right)-b\left(a-1\right)\)

= \(\left(a-1\right)\left(a^2x+ax+x-b\right)\)

f) \(x^2+2x-4y^2-4y\)

= \(x^2+2x+1-\left(4y^2+4y+1\right)\)

= \(\left(x+1\right)^2-\left(2y+1\right)^2\)

= \(\left(x+1-2y-1\right)\left(x+1+2y+1\right)\)

= \(\left(x-2y\right)\left(x+2y+2\right)\)

g) \(xy-4+2x-2y\)

= \(y\left(x-2\right)-2\left(x-2\right)\)

= \(\left(x-2\right)\left(y-2\right)\)

a: \(=\left(5x-5\right)^2-\left(4x-4y\right)^2\)

\(=\left(5x-5-4x+4y\right)\cdot\left(5x-5+4x-4y\right)\)

\(=\left(x+4y-5\right)\left(9x-4y-5\right)\)

b: \(=\left(x+1\right)^3-\left(3z\right)^3\)

\(=\left(x+1-3z\right)\left(x^2+2x+1+3xz+3z+9z^2\right)\)

c: \(=\left(x-y\right)^2-z\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-z\right)\)

d: \(=x\left(a^3-1\right)-b\left(a-1\right)\)

\(=x\left(a-1\right)\cdot\left(a^2+a+1\right)-b\left(a-1\right)\)

\(=\left(a-1\right)\left(a^2x+ax+1-b\right)\)

1 tháng 7 2017

chữ đẹp...rắn đẹp....rùa đẹphaha

9 tháng 7 2018

Bài 1 :

\(e,x^2+2xy+y^2-2x-2y+1\)

\(=\left(x+y-1\right)^2\)

Bài 2:

\(b,2x^3+3x^2+2x+3=0\)

\(\Leftrightarrow\left(2x^3+2x\right)+\left(3x^2+3\right)=0\)

\(\Leftrightarrow2x\left(x^2+1\right)+3\left(x^2+1\right)=0\)

\(\Leftrightarrow\left(x^2+1\right)\left(2x+3\right)=0\)

\(\Leftrightarrow2x+3=0\left(x^2+1>0\right)\)

\(\Leftrightarrow x=-\dfrac{3}{2}\)

Bài 1: Phân tích đa thức thành nhân tử: a) \(2x\left(x+1\right)+2\left(x+1\right)\) b) \(y^2\left(x^2+y\right)-zx^2-zy\) c) \(4x\left(x-2y\right)+8y\left(2y-x\right)\) d) \(3x\left(x+1\right)^2-5x^2\left(x+1\right)+7\left(x+1\right)\) e) \(x^2-6xy+9y^2\) f) \(x^3+6x^2y+12xy^2+8y^3\) g) \(x^3-64\) h) \(125x^3+y^6\) k) \(0,125\left(a+1\right)^3-1\) t) \(x^2-2xy+y^2-xz+yz\) q) \(x^2-y^2-x+y\) p) \(a^3x-ab+b-x\) đ)...
Đọc tiếp

Bài 1: Phân tích đa thức thành nhân tử:

a) \(2x\left(x+1\right)+2\left(x+1\right)\)

b) \(y^2\left(x^2+y\right)-zx^2-zy\)

c) \(4x\left(x-2y\right)+8y\left(2y-x\right)\)

d) \(3x\left(x+1\right)^2-5x^2\left(x+1\right)+7\left(x+1\right)\)

e) \(x^2-6xy+9y^2\)

f) \(x^3+6x^2y+12xy^2+8y^3\)

g) \(x^3-64\)

h) \(125x^3+y^6\)

k) \(0,125\left(a+1\right)^3-1\)

t) \(x^2-2xy+y^2-xz+yz\)

q) \(x^2-y^2-x+y\)

p) \(a^3x-ab+b-x\)

đ) \(3x^2\left(a+b+c\right)+36xy\left(a+b+c\right)+108y^2\left(a+b+c\right)\)

l) \(x^2-x-6\)

i) \(x^4+4x^2-5\)

m) \(x^3-19x-30\)

j) \(x^4+x+1\)

y) \(ab\left(a-b\right)+bc\left(b-c\right)+ca\left(c-a\right)\)

o) \(\left(a+b+c\right)^3-a^3-b^3-c^3\)

ê) \(4a^2b^2-\left(a^2+b^2+c^2\right)^2\)

w) \(\left(1+x^2\right)^2-4x\left(1-x^2\right)\)

z) \(\left(x^2-8\right)^2+36\)

u) \(81x^4+4\)

Bài 2 : Tìm x

a)\(\left(2x-1\right)^2-25=0\)

b) \(8x^3-50x=0\)

c) \(\left(x-2\right)\left(x^2+2+7\right)+2\left(x^2-4\right)-5\left(x-2\right)=0\)

d) \(3x\left(x-1\right)+x-1=0\)

e) \(2\left(x+3\right)-x^2-3x\) =0

f) \(4x^2-25-\left(2x-5\right)\left(2x+7\right)=0\)

g) \(x^3+27+\left(x+3\right)\left(x-9\right)=0\)

5
12 tháng 10 2017

Bài 1 :

a ) \(2x\left(x+1\right)+2\left(x+1\right)=\left(x+1\right)\left(2x+2\right)=2\left(x+1\right)^2\)

b ) \(y^2\left(x^2+y\right)-zx^2-zy=y^2\left(x^2+y\right)-z\left(x^2+y\right)=\left(x^2+y\right)\left(y^2-z\right)\)

c ) \(4x\left(x-2y\right)+8y\left(2y-x\right)=4x\left(x-2y\right)-8y\left(x-2y\right)=4\left(x-2y\right)^2\)

d ) \(3x\left(x+1\right)^2-5x^2\left(x+1\right)+7\left(x+1\right)=\left(x+1\right)\left(3x^2+3x-5x^2+7\right)=\left(x+1\right)\left(3x-2x^2+7\right)\)

e ) \(x^2-6xy+9y^2=\left(x-3x\right)^2\)

12 tháng 10 2017

Bài 1 :

f ) \(x^3+6x^2y+12xy^2+8y^3=\left(x+2y\right)^3\)

g ) \(x^3-64=\left(x-4\right)\left(x^2+4x+16\right)\)

h ) \(125x^3+y^6=\left(5x+y^2\right)\left(25x^2-5xy^2+y^4\right)\)

21 tháng 10 2020

cau a : (3x^2y-6xy+9x)(-4/3xy)

           =-4/3xy.3x^2y+4/3xy.6xy-4/3xy.9x

           =-4x+8-8y

cau b : (1/3x+2y)(1/9x^2-2/3xy+4y^2)

            =(1/3)^3-2/9x^2y+8y^3+4/3xy^2+2/9x^2y-4/3xy^2+8y^3

             =(1/3)^3 + (2y)^3x-2

cau c :  (x-2)(x^2-5x+1)+x(x^2+11)

            =x^3-5x^2+x-2x^2+10x-2+x^3+11x

            =2x^3-7x^2+22x-2

cau d := x^3 + 6xy^2 -27y^3

cau e := x^3 + 3x^2 -5x - 3x^2y - 9xy = 15y

cau f := x^2-2x+2x -4-2x-1

          = x(x-2)-5

21 tháng 10 2020

cau e la + 15y ko phai =15y

6 tháng 3 2020

\(x^2+4x-y^2+4\\ =\left(x^2+4x+4\right)-y^2\\ =\left(x+2\right)^2-y^2\\ =\left(x+2-y\right)\cdot\left(x+2+y\right)\)

\(2xy-x^2-y^2+16\\ =\left(x^2-2xy+y^2\right)-16\\ =\left(x-y\right)^2-16\\ =\left(x-y+4\right)\cdot\left(x-y-4\right)\)

\(x^2-2x-4y^2-4y\\ =\left(x^2-4y^2\right)-\left(2x+4y\right)\\ =\left(x-2y\right)\cdot\left(x+2y\right)-2\left(x+2y\right)\\ =\left(x+2y\right)\cdot\left(x-2y+2\right)\)

\(x^2+6x+9-y^2\\ =\left(x-3\right)^2-y^2\\ =\left(x-3-y\right)\cdot\left(x-3+y\right)\)

\(3x^2+6xy+3y^2-3z^2\\ =3\cdot\left(x^2+2xy+y^2-z^2\right)\\ =3\cdot\left[\left(x^2+2xy+y^2\right)-y^2\right]\\ =3\cdot\left[\left(x-y\right)^2-z^2\right]\\ =3\cdot\left(x-y-z\right)\cdot\left(x-y+z\right)\)

\(9x-x^3\\ =x\cdot\left(9-x^2\right)\\ =x\cdot\left(3-x\right)\cdot\left(3+x\right)\)

\(\left(2xy+1\right)^2-\left(2x+y\right)^2\\ =\left(2xy+1-2x-y\right)\cdot\left(2xy+1+2x-y\right)\)

5 tháng 10 2020

a) x2-y2-2x+2y

=(x+y)(x-y)-2(x-y)

=(x-y)(x+y-2)

b) 2x + 2y - x2 -xy

=2(x+y) - x(x+y)

=(x+y)(2-x)

c) 3a2 - 6ab + 3b2 - 12c2

= 3(a2+b2) -3(2ab+4c2)

= 3(a2+b2-2ab-4c2)

d) x2 - 25 + y2 + 2xy

= x2 + 2xy + y2 -25

= (x+y)2 - 52

= (x+y+5)(x+y-5)

e) x2y - x3 - 9y + 9x

= (9x - x3)+(x2y -9y)

= x(9-x2)+y(x2 - 9)

= x(9-x2)-y(9-x2)

= (9-x2)(x-y)

f) x2-2x-4y2-4y

= x2-4y2-2(x+2y)

=(x+2y)(x-4y)-2(x+2y)

=(x+2y)(x-4y-2)

câu g trùng với câu e

h) x2(x-1)+16(1-x)

= x2(x-1)-16(x-1)

= (x2-16)(x-1)

= (x+4)(x-4)(x-1)

27 tháng 8 2019

help me!!

a: \(A=2x^2-2xy-y^2+2xy=2x^2-y^2\)

\(=2\cdot\dfrac{4}{9}-\dfrac{1}{9}=\dfrac{7}{9}\)

b: \(B=5x^2-20xy-4y^2+20xy=5x^2-4y^2\)

\(=5\cdot\dfrac{1}{25}-4\cdot\dfrac{1}{4}\)

=1/5-1=-4/5

\(C=x^3+6x^2+12x+8=\left(x+2\right)^3=\left(-9\right)^3=-729\)

d: \(D=20x^3-10x^2+5x-20x^2+10x+4\)

\(=20x^3-30x^2+15x+4\)

\(=20\cdot5^3-30\cdot5^2+15\cdot2+4=1784\)