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a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
a) \(A=125\left(-24\right)+24.225\)
\(=24\left[\left(-125\right)+225\right]\)
\(=24.100=2400\)
b) \(B=26\left(-125\right)-125\left(-36\right)\)
\(=125\left[\left(-26\right)-\left(-36\right)\right]\)
\(=125.10=1250\)
c) \(C=25\left(75-45\right)-75\left(45-25\right)\)
\(=25.75-25.45-75.45-75.25\)
\(=\left(25.75-75.25\right)-25.45-75.45\)
\(=-25.45-75.45\)
\(=45\left(-25-75\right)\)
\(=45\left(-100\right)=-4500\)
a) (-25) + (-125) = -150
b) (-213) + (-27) = -240
c) (-26) + 78 = 52
d) 52 + (-102) = 50
e) (-37) + 84 = 47
f) (-723) + 23 = -700
a) = 150
b) = -240
c) = 52
d) = 50
e) = 47
f) = -700
Học tốt!!!
a) = 367 + 125 - 367 + 125
= (367 - 367) + (125+125)
= 0 + 250
= 250
b) = 29 - 614 + 386 + 71
= ( 29 + 71 ) - ( 614 + 386 )
= 100 - 1000
= - 900
\(\text{2045−(26+2019−56) }\)
\(\text{2045−(2045−56) }\)
\(\text{2045−1989 }\)
\(\text{56 }\)
\(\text{25.(78 - 125) - 125.(78 - 25)}\)
\(\text{25.−47−125.53 }\)
\(\text{25.−172.53}\)
thiếu phần b nha