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bài 1:
a)lấy mẫu chung là 12,ta có:4/12+5/12=9/12
câu tiếp bằng 5/9
lấy mẫu chung là 9,ta có:7/9-6/9=1/9
b)MSC:35 kết quả bằng 38/35
MSC:12 kết quả bằng -7/12
MSC:35 kết quả bằng 207/35
c)MSC:24 kết quả bằng 11/12
tương tự bằng 1/6
MSC:24 kết quả bằng 13/24
bài 2
a)x=8/2
b)x=6/7-2/3=4/21
c)x=7/3
bài 1 : chỉ cần quy đồng hai số cùng mẫu là đc
bài 2 : xác định thành phần của x rồi tinh
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\(x\times7\times9=\frac{10}{3}\)
\(x\times63=\frac{10}{3}\)
\(x=\frac{10}{3}:63\)
\(x=\frac{10}{189}\)
\(x\times\frac{2}{5}=\frac{1}{4}\times4\)
\(x\times\frac{2}{5}=1\)
\(x=1:\frac{2}{5}\)
\(x=\frac{5}{2}\)
\(x:\frac{1}{7}=\frac{1}{2}+\frac{3}{5}\)
\(x:\frac{1}{7}=\frac{11}{10}\)
\(x=\frac{11}{10}\times\frac{1}{7}\)
\(x=\frac{11}{70}\)
\(x:\frac{8}{9}=\frac{2}{9}+5\)
\(x:\frac{8}{9}=\frac{47}{9}\)
\(x=\frac{47}{9}\times\frac{8}{9}\)
\(x=\frac{376}{81}\)
a)X x 7x9 = 10/3 b) X x 2/5 =1/4 x4 c)X : 1/7 = 1/2 + 3/5
X \(\times\)7=\(\frac{10}{3}\div9\) X\(\times\frac{2}{5}=1\) \(x\div\frac{1}{7}=\frac{11}{10}\)
X\(\times\)7=\(\frac{10}{27}\) X\(=1\div\frac{2}{5}\) \(x=\frac{11}{10}\times\frac{1}{7}\)
X=\(\frac{10}{27}\)\(\div7\) X\(=\frac{5}{2}\) \(x=\frac{11}{70}\)
X=\(\frac{10}{198}\)
d)X : 8/9 =2/9 +5
\(x\div\frac{8}{9}=\frac{47}{9}\)
\(x=\frac{47}{9}\times\frac{8}{9}\)
\(x=\frac{376}{81}\)
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a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
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Tính nhanh mỗi biểu thức sau:
a, 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20
= (0 + 20) + (1 + 19) + (2 + 18) + (3 + 17) + (4 + 16) + (5 + 15) + (6 + 14) + (7 + 13) + (8 + 12) + (9 + 11) + 10
= 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 10
= 20 x 10 + 10
= 200 + 10
= 210
b, 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (4 x 9 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (36 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 0
= A x 0
= 0
c, (81 - 7 x 9 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (81 - 63 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (18 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 :(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 : A
= 0
d, (6 x 5 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (30 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (37 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x A
= 0
e, (11 x 9 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 + 1 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= (100 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= 0 : (1 x 2 x 3 x 4 x ... x 10)
= 0 : A
= 0
g, (m : 1 - m x 1) : (m x 2008 + m x 2008)
= (m - m) : (m x 2008 + m x 2008)
= 0 : (m x 2008 + m x 2008)
= 0 : A
= 0
h, (2 + 4 + 6 + 8 + m x n) x (324 x 3 - 972)
= (2 + 4 + 6 + 8 + m x n) x (972 - 972)
= (2 + 4 + 6 + 8 + m x n) x 0
= A x 0
= 0
l, (1 + 2 + 3 + ... + 99) x (13 x 15 - 12 x 15 - 15)
= (1 + 2 + 3 + ... + 99) x (15 x (13 - 12 - 1))
= (1 + 2 + 3 + ... + 99) x (15 x 0)
= (1 + 2 + 3 + ... + 99) x 0
= A x 0
= 0
i, (0 x 1 x 2 x...x 99 x 100) : (2 + 4 + 6 +...+ 98)
= 0 x : (2 + 4 + 6 +...+ 98)
= 0 x A
= 0
k, (0 + 1 + 2 +...+ 97 + 99) x (45 x 3 - 45 x 2 - 45)
= (0 + 1 + 2 +...+ 97 + 99) x (45 x (3 - 2 - 4))
= (0 + 1 + 2 +...+ 97 + 99) x (45 x 0)
= (0 + 1 + 2 +...+ 97 + 99) x 0
= A x 0
= 0
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Ta có : \(\left[x\cdot\frac{1}{2}+2\right]:\frac{3}{5}+4=9.\)
=> \(\left[x\cdot\frac{1}{2}+2\right]:\frac{3}{5}=9-4.\)
=> \(\left[x\cdot\frac{1}{2}+2\right]:\frac{3}{5}=5.\)
=> \(x\cdot\frac{1}{2}+2=5\cdot\frac{3}{5}.\)
=> \(x\cdot\frac{1}{2}+2=3.\)
=> \(x\cdot\frac{1}{2}=3+2.\)
=> \(x\cdot\frac{1}{2}=5.\)
=> \(x=5:\frac{1}{2}.\)
=> \(x=5\cdot2.\)
=> \(x=10.\)
Vậy x = 10 .
a)\(\left[x\times\frac{1}{2}+2\right]:\frac{3}{5}+4=9\) b)\(x\times\frac{2}{3}-\frac{1}{5}=\frac{2}{5}+1\)
\(\left[x\times\frac{1}{2}+2\right]:\frac{3}{5}=9-4\) \(x\times\frac{2}{3}-\frac{1}{5}=\frac{7}{5}\)
\(\left[x\times\frac{1}{2}+2\right]:\frac{3}{5}=5\) \(x\times\frac{2}{3}=\frac{7}{5}+\frac{1}{5}\)
\(x\times\frac{1}{2}+2=5\times\frac{3}{5}\) \(x\times\frac{2}{3}=\frac{8}{5}\)
\(x\times\frac{1}{2}+2=3\) \(x=\frac{8}{5}:\frac{2}{3}\)
\(x\times\frac{1}{2}=3-2\) \(x=\frac{8}{5}\times\frac{3}{2}\)
\(x\times\frac{1}{2}=1\) \(x=\frac{12}{5}\)
\(x=1:\frac{1}{2}\)
\(x=2\)
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a) 1/2x(3/4+2/5)
1/2x23/20
23/40
b) 3/4:(8/9+16/3)
3/4:56/9
27/224
c) 1/5:1/10-1/3
2-1/3
5/3
d) 3/4x(20/9-8/15)
3/4x76/45
19/15
e) 1/7:5/14-3/2
=2/5-3/2
-11/10 ( Chị nghĩ lớp 4 chưa học đến số âm nên em xem lại đề nhé)
g) 3/2x(11/6-5/12)
3/2x17/12
17/8
a)\(\frac{1}{2}x\left(\frac{3}{4}+\frac{2}{5}\right)\)
\(=\frac{1}{2}x\left(\frac{15}{20}+\frac{8}{20}\right)\)
\(=\frac{1}{2}x\frac{23}{20}\)
\(=\frac{23}{40}\)
b)\(\frac{3}{4}:\left(\frac{8}{9}+\frac{16}{3}\right)\)
\(=\frac{3}{4}:\left(\frac{8}{9}+\frac{48}{9}\right)\)
\(=\frac{3}{4}:\frac{56}{9}\)
\(=\frac{3}{4}x\frac{9}{56}\)
\(=\frac{27}{224}\)
c) \(\frac{1}{5}:\frac{1}{10}-\frac{1}{3}\)
\(=\frac{1}{5}x10-\frac{1}{3}\)
\(=2-\frac{1}{3}\)
\(=\frac{6}{3}-\frac{1}{3}=\frac{5}{3}\)
d) \(\frac{3}{4}x\left(\frac{20}{9}-\frac{8}{15}\right)\)
\(=\frac{3}{4}x\left(\frac{100}{45}-\frac{24}{45}\right)\)
\(=\frac{3}{4}x\frac{76}{45}\)
\(=\frac{19}{5}\)
e) \(\frac{1}{7}:\frac{5}{14}-\frac{3}{2}\)
\(=\frac{1}{7}x\frac{14}{5}-\frac{3}{2}\)
\(=\frac{2}{5}-\frac{3}{2}\)
\(=\frac{4}{10}-\frac{15}{10}\)
\(=\frac{-11}{10}\)
g) \(\frac{3}{2}x\left(\frac{11}{6}-\frac{5}{12}\right)\)
\(=\frac{3}{2}x\left(\frac{22}{12}-\frac{5}{12}\right)\)
\(=\frac{3}{2}x\frac{17}{12}\)
=\(=\frac{17}{8}\)
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\(\frac{7}{9}+\frac{9}{10}=\frac{70}{90}+\frac{81}{90}=\frac{70+81}{90}=\frac{151}{90}\)
\(1\frac{1}{10}-\frac{3}{4}=\frac{11}{10}-\frac{3}{4}=\frac{22}{20}-\frac{15}{20}=\frac{22-15}{20}=\frac{7}{20}\)
\(2\frac{1}{4}\)x\(3\frac{2}{5}\)=\(\frac{9}{4}\)x\(\frac{17}{5}=\)\(\frac{9x17}{4x5}=\frac{153}{20}\)
\(\frac{2}{5}:\frac{7}{9}=\frac{2}{5}\)x\(\frac{9}{7}=\frac{2x9}{5x7}=\frac{18}{35}\)
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Bài làm :
1)\(\frac{3}{2}+\frac{5}{2}-\frac{4}{2}=\frac{3+5-4}{2}=\frac{4}{2}=2\)
2)\(\frac{2}{5}\times\frac{1}{2}\div\frac{1}{3}=\frac{2\times1\times3}{5\times2\times1}=\frac{6}{10}=\frac{3}{5}\)
3)\(\frac{2}{9}\div\frac{9}{2}\times\frac{1}{2}=\frac{2\times2\times1}{9\times9\times2}=\frac{4}{162}=\frac{2}{81}\)
4)\(\left(\frac{4}{11}+\frac{3}{11}\right)\times\frac{2}{6}=\frac{4+3}{11}\times\frac{2}{6}=\frac{7}{11}\times\frac{2}{6}=\frac{7\times2}{11\times6}=\frac{14}{66}=\frac{7}{33}\)
TL:
9/2 x 1/3 + 1/5
9/6 + 1/5
45/30 + 6/30
51/30 = 17/10
HT
\(\frac{9}{2}\cdot\frac{1}{3}+\frac{1}{5}=\frac{3}{2}+\frac{1}{5}=\frac{17}{10}\)