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a)9.11.53+33.66.3+99
=99.53+99.66+99.1
=99(53+66+1)
=99.120
=11800
![](https://rs.olm.vn/images/avt/0.png?1311)
a ,[64+36]+[469+31]
=100+500
=600
b,[25.4].2018
=100.2018
=201800
mk sợ bạn chờ lâu
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9 . 11 . 53 + 33 . 46 . 3 + 99
= 9 . 11 . 53 + 33 . 3 . 46 + 99
= 99 . 53 + 99 . 46 + 99
= 99 . ( 53 + 46 ) + 99
= 99 . 99 + 99
= 9801 + 99
= 9900
9 . 11 . 53 + 33 . 46 . 3 + 99
= 99 . 53 + 99 . 46 + 99
= 99 . (53 + 46) + 99
= 99 . 99 + 99
= 9801 + 99
= 9900.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(\frac{x-99}{5}+\frac{x-99}{15}+\frac{x-99}{25}+\frac{x-99}{35}=0\)
\(\Rightarrow\left(x-99\right)\left(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+\frac{1}{35}\right)=0\)
Vì \(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+\frac{1}{35}\ne0\)
Nên : x - 99 = 0
Suy ra : x = 99
Vậy x = 99
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(...1\right)^{4k+3}=\left(....1\right);\left(...2\right)^{4k+3}=\left(...8\right);\left(.....3\right)^{4k+3}=\left(....7\right)\)
\(\left(....4\right)^{2k+1}=\left(....4\right);\left(....5\right)^k=\left(.....5\right);\left(....6\right)^k=\left(....6\right);\left(....7\right)^{4k+3}=3\)
\(\left(....8\right)^{4k+3}=\left(....2\right);\left(...9\right)^{2k+1}=\left(....1\right)\)
Tự áp dungj vào làm bài nha
\(99cod\text{ạng}:4k+1;2k+1;;;;;;99=k\left(\text{đ}\text{ạt}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(91-99+98)-(-99+98)=91-99+98+99-98=91
(99-98+97)-(99+97+98)=99-98+97-99-97-98=(-98)*2=-196
a)9.11.53+33.66.3+99
=99.53+99.66+99.1
=99(53+66+1)
=99.120
=11800
9.11.53+33.66.3+99
= 99.53+99.66+99.1
=99.(53+66+1)
=99.100=9900