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MSC: 504
\(\frac{40}{63}=\frac{40.8}{63.8}=\frac{320}{504}\)
\(\frac{35}{72}=\frac{35.7}{72.7}=\frac{245}{504}\)
\(\frac{19}{56}=\frac{19.9}{56.9}=\frac{171}{504}\)
a) - 72 . ( 15 - 49 ) + 15 . ( - 56 + 72 ) = -72 . -34 +15 . 16
= 2448 + 240
= 2688
b) 1532 + ( -168 ) + ( - 1432 ) + ( - 14 ) + 123 = 1364 + ( -1432) + ( -14) +123
= -68 + ( -14 ) +123
= -82 + 123 = 41
c) 75 - 5 . ( 15 - 40 ) - ( - 60 ) = 75 - 5 . (-25 )-(-60)
= 75 - (-125) - ( -60 )
= 200 - ( -60 ) = 260
d) | 31 -17 | - | 15 - 52 | = | 14 | - | -37 |
= 14 - 37
= -23
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
-72.(15-49)+15.(-56+72)
= -72.15+72.49+15.-56+15.72
=72.49+15.-56
=3528-840
=2688
a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
\(\dfrac{1}{6}x+\dfrac{1}{12}x+\dfrac{1}{20}x+...+\dfrac{1}{2450}x=1\)
\(x\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{2450}\right)\)=1
\(x\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{49\times50}\right)\)=1
\(x\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}\right)=1\)
\(x\left(\dfrac{1}{2}-\dfrac{1}{50}\right)=1\)
\(x\times\)\(\dfrac{12}{25}=1\)
\(\Rightarrow x=1\div\dfrac{12}{25}\)
\(x=1\times\dfrac{25}{12}=\dfrac{25}{12}\)
vậy \(x=\dfrac{25}{12}\)
vậy \(x=2\)\(x=2\)\(\Rightarrow\left(\dfrac{20}{9}-x\right)=\dfrac{1}{3}-\dfrac{1}{9}\)\(\left(2\dfrac{2}{9}-x\right)\)=\(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{72}\)
\(\Rightarrow\left(\dfrac{20}{9}-x\right)=\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{72}\)\(\Rightarrow\left(\dfrac{20}{9}-x\right)=\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+...+\dfrac{1}{8\times9}\)\(\Rightarrow\left(\dfrac{20}{9}-x\right)=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{8}-\dfrac{1}{9}\)
8x + 40 = 56 + 72
8x +40 = 128
8x = 128 - 40
8x = 88
x = 88 : 8
x = 11
8x + 40 = 56 + 72
8x + 40 = 128
8x = 128 - 40
8x = 88
x = 88 : 8
x = 11