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Ta có : A = ( 84/13 )2 + ( 35/13 )2 .
⇒ A = 842 / 132 + 352 / 132 .
⇒ A = ( 842 + 352 ) / 132 .
⇒ A = ( 7056 + 1225 ) / 169 .
⇒ A = 8281 / 169 .
⇒ A = 49 .
Vậy A = 49 .
![](https://rs.olm.vn/images/avt/0.png?1311)
A = \(\dfrac{21^2.14.125}{35^5.6}\)
= \(\dfrac{\left(3.7\right)^2.\left(2.7\right).5^3}{\left(5.7\right)^5.\left(2.3\right)}\)
= \(\dfrac{3^2.7^2.2.7.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3^2.7^3.2.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3}{5^2.7^2}\)
= \(\dfrac{3}{35^2}\)
@Pham Thi Thu Trang
B = \(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)
= \(\dfrac{2^{10}\left(13+65\right)}{2^8.104}\)
= \(\dfrac{2.78}{104}\)
= \(\dfrac{3}{2}\)
@Pham Thi Thu Trang
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Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
![](https://rs.olm.vn/images/avt/0.png?1311)
e) \(5^{13}:5^{10}-25.2^2\)
\(=5^3-5^2.2^2\)
\(=5^2\left(5-2^2\right)\)
\(=25\)
e) 513 : 510 - 25 . 22 f) 20:22+59:58 g) 100+ 52+ 7.32 h) 84:4+39:37+50 i) 29- [16+ 3. (51- 49)]
= 53 - 25 . 4 = 20 :4 + 5 = 100+ 25+ 7.9 = 21+ 32+ 1 = 29- [16+ 3.2 ]
=125 - 100 = 5+ 5 = 125+ 63 = 21+ 9+ 1 = 29- [16+ 6]
=25 = 10 = 188 = 31 = 29 - 22
=7
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\(a.2.x-138=2^3.3^2\)
\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x\) \(=72+138\)
\(2.x\) \(=210\)
\(x\) \(=210:2\)
\(x\) \(=105\)
\(b.231-\left(x-6\right)=1339:13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x\) \(=128+6\)
\(x\) \(=134\)
\(c.\left[\left(6.x-72\right):2-84\right].28=5628\)
\(\left[\left(6.x-72\right):2-84\right]\) \(=5628:28\)
\(\left(6.x-72\right):2-84\) \(=201\)
\(\left(6.x-72\right):2\) \(=201-84\)
\(\left(6.x-72\right):2\) \(=117\)
\(6.x-72\) \(=117.2\)
\(6.x-72\) \(=234\)
\(6.x\) \(=234+72\)
\(6.x\) \(=306\)
\(x\) \(=306:6\)
\(x\) \(=51\)
mik nè
\(=\left(\frac{84}{13}+\frac{35}{13}\right)^2-2\cdot\frac{84}{13}\cdot\frac{35}{13}\)
\(=7^2-\frac{5880}{169}\)
\(=49-\frac{5880}{169}\)
\(=\frac{8281}{169}-\frac{5880}{169}=\frac{2401}{169}\)
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