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a; (15 - \(\dfrac{121}{18}\)) : \(\dfrac{297}{27}\) - \(\dfrac{17}{8}\) : \(\dfrac{51}{40}\)
(\(\dfrac{270}{18}\) - \(\dfrac{121}{18}\)) : \(\dfrac{297}{27}\) - \(\dfrac{17}{8}\) x \(\dfrac{40}{51}\)
= \(\dfrac{149}{18}\) : \(\dfrac{297}{27}\) - \(\dfrac{5}{3}\)
= \(\dfrac{149}{18}\) x \(\dfrac{27}{297}\) - \(\dfrac{5}{3}\)
= \(\dfrac{149}{198}\) - \(\dfrac{5}{3}\)
= \(\dfrac{149}{198}\) - \(\dfrac{330}{198}\)
= \(\dfrac{-181}{198}\)
b; (- 3,2) x (- \(\dfrac{15}{64}\)) + (0,8 - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)
= (\(\dfrac{-16}{5}\)) x ( \(\dfrac{-15}{64}\)) + (\(\dfrac{4}{5}\) - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)
= \(\dfrac{3}{4}\) + (\(\dfrac{4}{5}\) - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)
= \(\dfrac{3}{4}\) + (\(\dfrac{12}{15}\) - \(\dfrac{34}{15}\)) : \(\dfrac{11}{3}\)
= \(\dfrac{3}{4}\) + \(\dfrac{-22}{15}\) : \(\dfrac{11}{3}\)
= \(\dfrac{3}{4}\) - \(\dfrac{22}{15}\) x \(\dfrac{3}{11}\)
= \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)
= \(\dfrac{15}{20}\) - \(\dfrac{8}{20}\)
= \(\dfrac{7}{20}\)
a, 48,63,80,99...
b, 288,399...
c,21,28,36,45,55,66,78,91...
d, 37,50,64,79,95...
C=-|x-15|-|x-+8|-24
=-(x-15)-(x-8)-24
=-x+15-x+8-24
=-2x+23-24
=-2x+(23-24)
=-2x+(-1)
Vậy C=-2x+(-1)
\(\frac{77}{176}=\frac{77:11}{176:11}=\frac{7}{16}\) ; \(\frac{232323}{474747}=\frac{232323:10101}{474747:10101}=\frac{23}{47}\)
\(\frac{376376}{159159}=\frac{376376:1001}{159159:1001}=\frac{376}{159}\) ; \(\frac{9\cdot8\cdot5}{24\cdot15}=\frac{9\cdot8\cdot5}{8\cdot3\cdot3\cdot5}=\frac{9\cdot8\cdot5}{8\cdot9\cdot5}=1\)
\(\frac{9.8.5}{24.15}\)
\(=\frac{9.8.5}{8.3.3.5}\)
\(=1\)
a, 15 + x = 7
X= 7-15
x= -8
b, x - 9 = -24
x= -24+9
x= -15
c, - x + 8 = - 22
-x = -22-8
-x=-30
x=30
`-8/3xx15/24`
`=-8/3xx5/8`
`=-5/3`
\(\dfrac{-8}{3}.\dfrac{15}{24}=\dfrac{-8}{3}.\dfrac{5}{8}=\dfrac{-8.5}{3.8}=\dfrac{-5}{3}\)