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-7.(3x-5)+2.(7x-14)=28
-21x-35+14x-28=28
-21x+14x=28+35+28
-7x=94
x=94/-7
Vậy.................................
\(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x=21\)
\(\Leftrightarrow x=-3\)
Vậy : \(x=-3\)
\(-7\left(3x-5\right)+2\left(7x-14\right)=28\\ -21x+35+14x-28=28\\ -7x+7=28\\ -7x=21\\ x=-3\)
-7(3x - 5) + 2(7x - 14) = 28
-21x + 35 + 14x - 28 = 28
-7x = 28 - 35 + 28
-7x = 21
x = 21 : (-7)
x = -3
\(-7.\left(3x-5\right)+2.\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x+7=28\)
\(\Leftrightarrow-7x=21\)
\(\Leftrightarrow x=-3\)
Vậy \(x=-3\)
a: =>x/27+1=-2/3
=>x/27=-5/3
=>x=-45
b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)
=>x=221/50
c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)
=>x=1/15-2/3=1/15-10/15=-9/15=-3/5
d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)
=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)
=>x=-37/24
e: =>-3/7x=84/45
=>x=-196/45
f: =>11/10x=-2/3
=>x=-20/33
7x - 28 : 4 = 14
7x - 7 = 14
7x = 14 + 7 = 21
=> x = 21 : 7
=> x = 3
7x - 28 : 4 = 14
7x - 7 = 14
7x =14+7
7x =21
x =21:7
x =3
**** nhé