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750 : {130 – [(5 . 14 – 65)3 + 3]}
= 750 : {130 – [(70 – 65)3 + 3]}
= 750 : {130 – [(5)3 + 3]}
= 750 : (130 – 128)
= 750 : 2
= 375

a)\(72.19 - 36^2:18= 72.19- 36.36:18\)
\(=72.19 - 72=72.(19 - 1)\)
\(=72.18=1296\)
b)
\(\begin{array}{l}750{\rm{ }}:{\rm{ }}\left\{ {130{\rm{ }} - {\rm{ }}[{{\left( {5.{\rm{ }}14{\rm{ }} - {\rm{ }}65} \right)}^3} + {\rm{ }}3} \right\}\\ = 750{\rm{ }}:{\rm{ }}\left\{ {130{\rm{ }} - {\rm{ }}\left[ {{{\left( {{\rm{70 }} - {\rm{ }}65} \right)}^3} + {\rm{ }}3} \right]} \right\}\\ = 750{\rm{ }}:{\rm{ }}\left\{ {130{\rm{ }} - {\rm{ }}\left[ {{5^3} + {\rm{ }}3} \right]} \right\}\\ = 750{\rm{ }}:{\rm{ }}\left\{ {130{\rm{ }} - {\rm{ }}\left[ {125 + {\rm{ }}3} \right]} \right\}\\ = 750{\rm{ }}:{\rm{ }}\left\{ {130{\rm{ }} - {\rm{ 128}}} \right\}\\ = 750:2 = 375.\end{array}\)

CÂU 1
\(5^{n+1}+5^n=750\)
\(=>5^n\cdot5+5^n=750\)
\(=>5^n\cdot\left(5+1\right)=750\)
\(=>5^n\cdot6=750\)
\(=>5^n=750:6\)
\(=>5^n=125\)
\(=>5^n=5^3\)
\(=>n=3\)

A =118.75
B=125 -5 .(3.X -1) =25
5.(3.X-1) =100
3.X-1=20
3X =21
X=7

[130 - 3.(5.24 - 52.2) : 23]
= [ 130 - 3.30:23]
= 130 - 11,25
= 118,75
b) 125 -5.(3x-1) = 55:53
125 -5.(3x-1) = 25
5.(3x-1) = 100
3x-1 = 20
3x = 21
x = 7
c) 4x-1 + 40 = 65
4x:4 + 1 = 65
4x:4 = 64
4x = 256 = 44
=> x = 4


(315.4+314.15):316
=(315.4+314.3.5):316
=(315.4+315.5):316
=[315.(4+5)]:316
=[315.9]:316
=315.32:316
=3

Bài 1:
a) 12.18 + 14.3 - 255 : 17
= 216 + 42 - 15
= 258 - 15
= 243
b) 15.8 - (83 - 30 + 17) - 144 : 6
= 15.8 - (53 + 17) - 144 : 6
= 15.8 - 70 - 144 : 6
= 120 - 70 - 144 : 6
= 120 - 70 - 24
= 50 - 24
= 26
c) 24.(15 + 30 + 85 - 120) : 10
= 24.(45 + 85 - 120) : 10
= 24.(130 - 120) : 10
= 24.10 : 10
= 24.1
= 24
d) 15 - 25.8 : (100.2)
= 15 - 25.8 : 200
= 15 - 200 : 200
= 15 - 1
= 14
e) 32.5 - 22.7 + 1.5
= 9.5 - 4.7 + 1.5
= 45 - 28 + 5
= 17 + 5
= 22
g) (24.5 - 52.2) : (5.2) - 3
= (24.5 - 25.2) : (5.2) - 3
= (120 - 50) : 10 - 3
= 70 : 10 - 3
= 7 - 3
= 4
h) [(52.23 - 72.2) : 2].6 - 7.25
= [(25.8 - 49.2) : 2].6 - 7.32
= [(200 - 98) : 2].6 - 224
= [102 : 2].6 -224
= 51.6 - 224
= 306 - 224
= 82
i) 27 : 22 + 54 : 53.24 - 3.25
= 25 + 5.24 - 3.25
= 32 + 5.16 - 3.32
= 32 + 80 - 96
= 112 - 96
= 16
k) (37.35) : 310 + 5.24 - 73 : 7
= 312 : 310 + 5.24 - 72
= 32 + 5.24 - 72
= 9 + 5.16 - 49
= 9 + 80 - 49
= 89 - 49
= 40
Bài 2:
a) 547 + 389 + 453 + 211
= (547 + 453) + (389 + 211)
= 1000 + 600
= 1600
b) 125.98.2.8.25
= (125.8).(25.2.98)
= 1000.4900
= 4900000
c) 8466.15 + 170.4233
= 4233.2.15 + 170.4233
= 4233.30 + 170.4233
= 4233.(30 + 170)
= 4233. 200
= 846600
d) (62007 - 62006) : 62006
= 62007 : 62006 - 62006 : 62006
= 6 - 1
= 5
e) (112003 + 112002) : 112002
= 112003 : 112002 + 112002 : 112002
= 11 + 1
= 12
f) 4.24.52 - (33.18 + 33.12)
= 4.24.25 - [33.(18 + 12)]
= 4.25.24 - [27.30]
= 100.24 - 810
= 2400 - 810
= 1590
g) 23.7.53- (52.65 + 52.35)
= 8.7.125 - (25.65 + 25.35)
= 8.125.7 - [25.(65 + 35)]
= 1000.7 - [25.100]
= 7000 - 2500
= 4500
Xin lỗi nha, nhìu quá mk lm ko hết, thông cảm cho mk.

a)\(-7-25+27+5=\left(27-7\right)+\left(5-25\right)\)
\(=20-20=0\)
b)\(-8+16-\left(-8\right)=-8+16+8=\left(8-8\right)+16=16\)
c)\(1+1-\left(-8\right)=1+1+8=10\)(Vì số nào mũ 0 cũng bằng 1(ngoại trừ số 0))
d)\(65.23+65.35-35.65+35.23\)
\(=\left(65.35-65.35\right)+23.\left(65+35\right)\)
\(=0+23.100=2300\)
f) \(8+\left[1800-\left(64-54\right)^3\right].8-5\)
\(=8+\left(1800-10^3\right).8-5\)
\(=8+800.8-5=6403\)
h)\(-123-46+46+123=\left(123-123\right)+\left(46-46\right)\)
\(=0+0=0\) (phá ngoặc ra thôi nhé)
\(=750:\left\{130-\left[125+3\right]\right\}=750:\left\{130-128\right\}=750:2=375\)
\(750:\left(130-\left(70-65\right)^3+3\right)\)
\(750:\left(130-\left(5^3+3\right)\right)\)
\(750:\left(130-\left(125+3\right)\right)\)
\(750:\left(130-128\right)=750:2=375\)
Bàn phím mình không viết được ngoặc nhọn,ngoặc vuông nha bạn