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a) =-5/7 +7/8-2/7+1/8- -1/12+ -13/12
=(-5/7-2/7)+(7/8+1/8)-(-1/12--13/12)
=-7/7+8/8 - 12/12
= -1+1+1
=1
b)= ( -3/8+11/8)-(12/11+ -1/11)+(-3/5- 2/5)
= 1- 1 + (-1)
=-1
\(a)\frac{2}{3}x-\frac{1}{2}=\frac{5}{12}\)
\(\Rightarrow\frac{2}{3}x=\frac{5}{12}+\frac{1}{2}=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}:\frac{2}{3}=\frac{11}{8}\)
\(b)\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\Rightarrow\frac{14}{5}x-50=51.\frac{2}{3}=34\)
\(\Rightarrow\frac{14}{5}x=34+50=84\)
\(\Rightarrow x=84:\frac{14}{5}=30\)
a) 2/3.x - 1/2 = 5/12
2/3.x = 5/12 + 1/2
2/3.x = 11/12
x = 11/12 : 2/3
x = 11/8
b) \(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
\(\frac{14}{5}.x-50=51.\frac{2}{3}\)
\(\frac{14}{5}.x-50=34\)
\(\frac{14}{5}.x=34+50\)
\(\frac{14}{5}.x=84\)
\(x=84:\frac{14}{5}\)
\(x=30\)
\(P=\frac{1}{5^2}+\frac{2}{5^3}+\frac{3}{5^4}+\frac{4}{5^5}+...+\frac{11}{5^{12}}\)
\(\Rightarrow\)\(5P=\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+\frac{4}{5^4}+...+\frac{11}{5^{11}}\)
\(\Rightarrow\)\(4P=\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+\frac{1}{5^4}+...+\frac{1}{5^{11}}-\frac{1}{5^{12}}\)
\(\Rightarrow\)\(20P=1+\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{10}}-\frac{1}{5^{11}}\)
\(\Rightarrow\)\(16P=1-\frac{1}{5^{11}}+\frac{1}{5^{12}}-\frac{1}{5^{11}}\)\(< 1\)
\(\Rightarrow\)\(P< \frac{1}{16}\)
P/s: nguyên tác: https://olm.vn/thanhvien/nhatphuonghocgiot
\(0,5.1\frac{1}{3}.75\%:\frac{2}{5}+\frac{3}{5}\)
\(=\frac{1}{2}.\frac{4}{3}.\frac{3}{4}:\frac{2}{5}+\frac{3}{5}\)
\(=\frac{1}{2}.\frac{4}{3}.\frac{3}{4}.\frac{5}{2}+\frac{3}{5}\)
\(=\frac{5}{4}+\frac{3}{5}\)
\(=\frac{37}{20}\)
\(0,5.1\frac{1}{3}.75\%:\frac{2}{5}+\frac{3}{5}\)
\(=\frac{1}{2}.\frac{4}{3}.\frac{3}{4}:\frac{2}{5}+\frac{3}{5}\)
\(=\frac{1}{2}.\frac{4}{3}.\frac{3}{4}.\frac{5}{2}+\frac{3}{5}\)
\(=\frac{1.4.3.5}{2.3.4.2}+\frac{3}{5}\)
\(=\frac{5}{4}+\frac{3}{5}\)
\(=\frac{37}{20}\)
~Học tốt~
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{8}{12}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(x=\frac{10}{12}-\frac{1}{12}\)
\(x=\frac{9}{12}\) \(=\frac{3}{4}\)
<=> 5/6 - x = 1/12
<=> -x = 1/12 - 5/6
<=> -x = -3/4
=> x = 3/4
Vậy x = 3/4
\(C=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{72}+\frac{1}{90}\)
\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+....+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}\)
\(=\frac{15}{20}-\frac{30}{20}+\frac{24}{20}\)
\(=\frac{9}{20}\)
bt rùi nhưng ko chắc lắm