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a) 23.15 - [115 - (12-5)2]
= 8.15 - [115 - 72]
= 120 - [115 - 49]
= 120 - 66
= 54
b) 30 : {175 : [355 - (135+37.5)]}
= 30 : {175 : [355 - (135 + 185)]}
= 30 : {175 : [355 - 320]}
= 30 : {175 : 35}
= 30 : 5
= 6
c) 12 : {390 : [500 - (125+35.7)]}
= 12 : {390 : [500 - (125+245)]}
= 12 : {390 : [500 - 370]}
= 12 : {390 : 130}
= 12 : 3
= 4
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a) 248 + (-12) + 2064 + (-236)
= 248 - 236 + 2064 - 12
= 12 + 2052
= 2064
b) [ ( -355 ) + 215 + ( -145 )]
= [ - ( 355 - 215 ) + ( -145 ) ]
= [ ( -140 ) + ( -145 ) ]
= -285
c) ( - 357 ) + 0
= - ( 357 - 0 )
= -357
d) 251 + 0 + ( -312 )
= 251 + ( -312 )
= - ( 312 - 251 )
= - 61
HT~
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a) -(3x - 5) - (-5x - 7 ) = 6
-3x + 5 + 5x + 7 = 6
( -3 + 5 )x + 5 + 7 = 6
2x + 12 = 6
2x = -6
x = -3
c) -5x - 17 = -2x + 4
-5x + 2x = 4 + 17
-3x = 21
x = -7
a) -(3x-5)-(-5x-7) =6
-3x+5 +5x+7 =6
(-3x+5x)+(5+7)=6
[(-3+5)x]+ 12 =6
2x + 12 =6
2x =6-12
2x =-6
x=-6:2
x=-3
b) (-5x-12)-(x+3) =1
-5x-12 - x-3 =1
(-5x-x) -(12-3)=1
(-5x-1x) - 9 =1
[(-5-1)x] - 9 =1
-6x-9=1
-6x=1+9
-6x=10
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Gọi số sách cần tìm là a (725\(\le\)a\(\le\)1000)
Ta có: a chia hết cho 10
a : 12 dư 2 =>a-2 chia hết cho 12
a : 18 dự 8 =>a-8 chia hết cho 18
=> a-10 chia hết cho{10,12,18}
=> a-10\(\in\)BC(10,12,18)
Mà BCNN(10,12,18)=22.32.5=180=>BC(10,12,18)=B(180)={0,180,360,540,720,900,1080,...}
Vì 725\(\le\)a\(\le\)1000=> a-10=900 =>a=890
Vậy số sách là 890
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a. -12 + x = 5x - 20
<=> 4x = 8
<=> x = 2
b. 7x - 4 = 20 + 3x
<=> 4x = 24
<=> x = 6
c. 5x - 7 = -21 - 2x
<=> 7x = -14
<=> x = -2
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1) 3x - 6 = 5x + 2
=> 3x - 5x = 2 + 6
=> -2x = 8
=> x = -4
2) 15 - x = 4x - 5
=> 15 + 5 = 4x + x
=> 20 = 5x
=> x = 4
3) x - 15 = 6 + 4x
=> x - 4x = 6 + 15
=> -3x = 21
=> x = -7
4) -12 + x = 5x - 20
=> x - 5x = -20 + 12
=> -4x = -8
=> x = 2
5) 7x - 4 = 20 + 3x
=> 7x - 3x = 20 + 4
=> 4x = 24
=> x = 6
1) 3x- 6 = 5x + 2
5x - 3x = -6 - 2
2x = -8 => x = -4
Tương tự như trên
\(725-5x=355\)
\(5x=725-355=370\)
\(x=370:5=74\)
725 - 5x = 355
=> 5x = 725 - 355
=> 5x = 370
=> x = 74