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\(7^{13}:49^2=7^{13}:7^4=7^9\)
\(27^{16}:9^{10}=3^{48}:3^{20}=3^{28}\)
\(5^{20}\cdot9^{10}=5^{20}\cdot3^{20}=15^{20}\)
\(7^7\cdot13+7^7\cdot36=7^7\cdot\left(13+36\right)=7^7\cdot49=7^7\cdot7^2=7^9\)
\(5^{12}\cdot37-5^{12}\cdot12=5^{12}\cdot\left(37-12\right)=5^{12}\cdot25=5^{12}\cdot5^2=5^{14}\)
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a,5mũ 36=(5mũ3)mũ12=125 mũ12
11^24=(11^2)12=121^12
vì 121<125 nên 5^36>11^24
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a,( 393+390) : (317. 373)
= (33+1). 390 : 390
= 33+1
=27+1
=28
b,(556+57) : (549+1)
=57. (549+1) : (549+1)
=57= 78125
c,(722+721+720) ; (25+24+32)
= 720. (72+71+1) : [24. (2+1)+32 ]
= 720. 57 : [ 24. 3 +32 ]
= 720. 57 : ( 24+3) . 3
= 720. 57 : 19 . 3
= 720. 57 : 57
= 720
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\(7^x\times49=7^{32}\)
\(\Rightarrow7^x\times7^2=7^{32}\)
\(\Rightarrow7^{x+2}=7^{32}\)
\(\Rightarrow x=30\)
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7A=7^2+7^3+7^4+....+7^100
A=7+7^2+7^3+....+7^99
6A=7^100-7
khi đó ta có
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1+7+7 mũ 2+7 mũ 3......+7 mũ 100.Tính a,a là tổng dãy số trên
739 + 49 = 739 + 72 = 72(737 + 1)
=> \(\frac{7^{39}+49}{7^{37}+1}=\frac{7^2\left(7^{37}+1\right)}{7^{37}+1}=7^2=49\)
Vậy : ...
\(\left(7^{39}+49\right):\left(7^{37}+1\right)\)
\(=\left(7^{39}+7^2\right):\left(7^{37}+1\right)\)
\(=7^2\left(7^{37}+1\right):\left(7^{37}+1\right)\)
\(=7^2.1\)
\(=49\)
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