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A) 3/7 + 4/9 + 4/7 + 5/9 = ( 4/9+5/9) + ( 3/7 + 4/7) = 1+ 1 = 2
B) 1/5 + 4/11 + 4/5 + 7/11 = ( 4/11 + 7/11) + ( 1/5 + 4/5) = 1+1=2
C) 1/15 + 4/15 + 5/18 + 7/18= ( 1/15+4/15) + (5/18+7/15)= 5/15 + 12/15 = 17/15
D) 1/8 + 1/12 + 3/8 + 5/12 = (1/8 + 3/8) + ( 1/12 + 1/12) = 4/8 + 2/12 = 64/96
K nha
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Ta có:
A = [15 x (1-1/7-1/12-1/98)] / [ 18 x (1-1/7-1/12-1/98)]
= 15/18 = 5/6
\(A=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}=\frac{15}{18}=\frac{15:3}{18:3}=\frac{5}{6}\)
k cho mk nha
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1) \(\frac{1}{12}+\frac{1}{16}+\frac{3}{4}\)
\(=\frac{4}{48}+\frac{3}{48}+\frac{36}{48}\)
\(=\frac{4+3+36}{48}\)
\(=\frac{43}{48}\)
2) a) \(\frac{1}{15}+\frac{4}{15}+\frac{5}{18}+\frac{7}{18}\)
\(=\left(\frac{1}{15}+\frac{4}{15}\right)+\left(\frac{5}{18}+\frac{7}{18}\right)\)
\(=\frac{1}{3}+\frac{2}{3}=1\)
b) \(\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(=\left(\frac{1}{8}+\frac{3}{8}\right)+\left(\frac{1}{12}+\frac{5}{12}\right)\)
\(=\frac{1}{2}+\frac{1}{2}=1\)
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a,18/15+7/15+12/15=18+7+12/15
=37/15
b,9/7+8/7+11/7=9+8+11/7
=28/7=1/4
+8/15 + 7/15 +12/15 = (18+7+12)/7 = [(18+12)+7]/15= (30+7)/15=37/15=7/3
9/7 + 8/7 + 11/7 = (9+8+11)/7= [(9+11)+8]/7=(20+8)/7= 28/7 =4
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a) 1/3 + 3/4 - 7/12
= 4/12 + 9/12 - 7/12
= 6/12
= 1/2
b) 6/11 : 5/22 - 4/5
= 6/11 * 22/5 - 4/5
= 12/5 - 4/5
= 8/5
c) 5/18 * 8
= 40/18
= 20/9
d) 7/15 : 5
= 7/15 * 1/5
= 7/75
OK
a, \(\frac{1}{3}+\frac{3}{4}-\frac{7}{12}\)
= \(\frac{13}{12}-\frac{7}{12}\)
= \(\frac{1}{2}\)
\(b,\frac{6}{11}:\frac{5}{22}-\frac{4}{5}\)
= \(\frac{12}{5}-\frac{4}{5}\)
\(=\frac{8}{5}\)
\(c,\frac{5}{18}x8\)
=\(\frac{20}{9}\)
\(d,\frac{7}{15}:5\)
= \(\frac{7}{15}x\)\(\frac{1}{5}\)
\(=\frac{7}{75}\)
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\(\dfrac{14}{21}=\dfrac{2}{3}\\ \dfrac{12}{15}=\dfrac{8}{10}\\ \dfrac{5}{7}=\dfrac{20}{28}\\ \dfrac{18}{33}=\dfrac{6}{11}\)
a, 5/4 , 14/21 , 12/15 , 5/7 , 18/33
b, 20/28 , 15/12 , 6/11 , 2/3 , 8/10
14/21=2/3
20/28=5/7
18/33=6/11
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a ) \(\frac{1}{15}+\frac{4}{15}+\frac{5}{18}+\frac{7}{18}\)
\(=\left(\frac{1}{15}+\frac{4}{15}\right)+\left(\frac{5}{18}+\frac{7}{18}\right)\)
\(=\frac{1}{3}+\frac{2}{3}\)
\(=1\)
b ) \(\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(=\left(\frac{1}{8}+\frac{3}{8}\right)+\left(\frac{1}{12}+\frac{5}{12}\right)\)
\(=\frac{1}{2}+\frac{1}{2}\)
\(=1\)
a, \(\frac{1}{15}\)+ \(\frac{4}{15}\)+ \(\frac{5}{18}\)+ \(\frac{7}{18}\)= ( \(\frac{1}{15}\)+ \(\frac{4}{15}\)) + ( \(\frac{5}{18}\)+ \(\frac{7}{18}\))
= \(\frac{1}{3}\)+ \(\frac{2}{3}\)
= \(\frac{3}{3}\)= 1
b,\(\frac{1}{8}\)+ \(\frac{1}{12}\)+ \(\frac{3}{8}\)+ \(\frac{5}{12}\)= ( \(\frac{1}{8}\)+ \(\frac{3}{8}\)) + ( \(\frac{1}{12}\)+ \(\frac{5}{12}\))
= \(\frac{1}{2}\)+ \(\frac{1}{2}\)
= \(\frac{2}{2}\)= 1
\(\frac{7}{12}+\frac{7}{15}x\frac{5}{18}\)
\(=\frac{7}{12}+\frac{7}{34}\)
\(=\frac{238}{408}+\frac{84}{408}\)
\(=\frac{322}{408}=\frac{162}{204}\)