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a) 6x + x = 511 : 59 + 31
6x + x = 52 + 31
7x = 25 + 3
7x = 28
x = 28 : 7
x = 4
b) 7x - x = 521 : 59 + 3 . 22 - 70
6x = 512 + 3 . 4 - 1
6x = 244140625 + 12 - 1
6x = 244140636
x = 244140636 : 6
x = 40690106
a)6x +x = 511 :59 +31
(6+1)x=52 +3
7x =25 +3=28
x = 28 :7
x=4
Vậy x=4
b) 7x-x = 521 : 59 +3 . 22 - 7
(7-1)x = 512 +3.4-1
6x= 244140625 + 12 - 1
6x = 244140637-1=244140636
x=244140636:6
x=40690106
Vậy x= 40690106
\(5x+2x=6^2-5^0\Leftrightarrow5x+2x=6^2-1\)
\(\Leftrightarrow5x-2x=36-1\Leftrightarrow5x-2x=35\Leftrightarrow x\left(5+2\right)=35\)
\(\Leftrightarrow7x=35\Leftrightarrow x=35:7\Leftrightarrow x=5\)
\(5x+x=150:2+3\Leftrightarrow5x+x=75+3\)
\(\Leftrightarrow5x+x=78\Leftrightarrow x\left(5+1\right)=78\Leftrightarrow x6=78\)
\(\Leftrightarrow x=78:6\Leftrightarrow x=13\)
a) 5x + 2x = 62 - 50
7x = 35 => x = 5
b) 5x + x = 150 : 2 + 3
6x = 78 => x = 13
c) 6x + x = 511 : 59 + 31
7x = 28 => x = 4
d) 5x + 3x = 36 : 33 x 4 + 12
8x = 120 => x = 15
e) 4x + 2x = 68 - 219 : 216
6x = 60 => x = 10
f) 5x + x = 39 - 311 : 39
6x = 30 => x = 5
g) 7x - x = 521 : 519 + 3 x 22 - 70
6x = 36 => x = 6
h) 7x - 2x = 617 : 615 + 44 : 11
5x = 40 => x = 8
Bài 1:
520 : [ 515 . 6 + 515 . 19 ]
= 520 : [ 515 . ( 6 + 19 ) ]
= 520 : [ 515 . 25 ]
= 520 : [ 515 . 52 ]
= 520 : 517
= 53
Bài 2
a) 5x + x = 39 - 311 : 39
=> 6x = 39 - 32
=> 6x = 39 - 9
=> 6x = 30
=> x = 5
b) 7x - x = 521 : 519 + 3 . 22 - 70
=> 6x = 52 + 3 . 4 - 1
=> 6x = 25 + 12 - 1
=> 6x = 36
=> x = 6
c) 7x - 2x = 617 : 615 + 44 : 11
=> ( 7 - 2 )x = 62 + 4
=> 5x = 36 + 4
=> 5x = 40
=> x = 8
1. \(5^{20}:\left(5^{15}.6+5^{15}.19\right)=5^{20}:\left\{5^{15}\left(6+19\right)\right\}\)
\(=5^{20}:\left\{5^{15}.25\right\}=5^{20}:\left\{5^{15}.5^2\right\}\)
\(=5^{20}:5^{17}=5^3=125\)
a , 6x + x=5¹¹ : 5⁹ + 3¹
7x= 5²+ 3¹
7x = 25+3
7x = 28
x = 4
Bài 1:
a)12,5 x (-5/7) + 1,5 x (-5/7)
=-5/7*(12,5+1,5)
=-5/7*14
=-10
b)(-1/4) x (6|2/11) + 3|9/11 x (-1/4)
=-1/4*(68/11+42/11)
=-1/4*10
=-5/2
c tương tự
d)\(\frac{9^8\cdot4^3}{27^4\cdot6^5}=\frac{\left(3^2\right)^8\cdot\left(2^2\right)^3}{\left(3^3\right)^4\cdot\left(2\cdot3\right)^5}=\frac{3^{16}\cdot2^6}{3^{12}\cdot2^5\cdot3^5}=\frac{3^{16}\cdot2^5\cdot2}{3^{16}\cdot3^1\cdot2^5}=\frac{2}{3}\)
Bài 2:
a)Ta có:
2800=(28)100=256100
8200=(82)100=64100
Vì 256100>64100 =>2800>8200
b)Ta có:
1245=(123)15=172815
Vì 62515<172815 =>62515<1245
a,12,5x(-5/7)+1,5x(-5/7)
=-125/14+-15/14
=-10
2,2mu800>8 mu 200
6254 lon hon 12
(7x-11)3=25.52+200
=> (7x-11)3=800+200
=> (7x-11)3=1000
=> (7x-11)3=103
=> 7x - 11 = 10
=> 7x = 21
=> x = 3
(2x-15)5=(2x-15)3
=> (2x-15)5 - (2x-15)3 = 0
=> (2x-15)3 . [ (2x-15)2 - 1 ] = 0
=> \(\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=1\end{cases}\Rightarrow}\orbr{\begin{cases}2x=15\\2x=16\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{15}{2}\\x=8\end{cases}}}\)
Mà x thuộc N
=> x = 8
(3x-5)10=(3x-5)9
=> (3x-5)10 - (3x-5)9 = 0
=> (3x-5)9 .[ (3x-5) - 1 ] = 0
=> \(\orbr{\begin{cases}\left(3x-5\right)^9=0\\\left(3x-5\right)-1=0\end{cases}\Rightarrow\orbr{\begin{cases}3x-5=0\\3x-5=1\end{cases}\Rightarrow}\orbr{\begin{cases}3x=5\\3x=6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=2\end{cases}}}}\)
Mà x thuộc N
=> x = 2
a)(7x-11)^3=1000
(7x-11)^3=10^3
7x-11 =10
7x =10+11=21
x =21:7=3
\(\left(x-6\right)^2=9=3^2=\left(-3\right)^2=>\orbr{\begin{cases}x-6=3\\x-6=-3\end{cases}}=>\orbr{\begin{cases}x=9\\x=3\end{cases}}\)
\(5^{x+1}=125=5^3=>x+1=3=>x=2\)
\(5^{2x-3}-2.5^2=3.5^2=>5^{2x-3}=3.5^2+2.5^2=\left(3+2\right).5^2=5.5^2=125=5^3\)
\(=>2x-3=3=>2x=6=>x=3\)
6x+x=5^11-9+3^1
6x+x=5^2+3
6x+x=25+3
7x=28
=>x=28:7
=>x=4
tick nha
6x+x=5^11:5^9+3^1
6x+x=48828125:1953125+3
6x+x=25+3
6x+x=28
Vậy x=4 vì 6.4+4=28
6x+x=5^11:5^9+3^1
x.(6+1)=5^2+3
x.7=25+3
x.7=28
x=28:7
x=4
vậy x=4
k mk nha
6x+x=5^11:5^9+3^1
<=>7x=5^(11-9)+3
<=>7x=5^2+3
<=>7x=28
<=>x=4