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a) 19 + 19 . 99 + 25 . 4
= 19 . (99+1) + 25 . 4
= 19 . 100 + 25 . 4
= 1900 + 100
= 2000.
b) 2 . [( 7 - 33 : 32 ) : 22 + 99 ] - 100
= 2. [( 7 - 3 ) : 4+ 99 ] - 100
= 2. ( 4 : 4 + 99 ) - 100
= 2. 100 -100
= 100.
c) | - 5 + 9 | + ( -29 + 5 )
= 4 + (-24)
= -20.

a) 19 + 19 . 99 - 25 . 4
= 19 . 100 - 25 . 4
= 1900 - 100
= 1800
b) 2 . [(7 - 33 : 32) : 22 + 99] - 100
= 2 . [(7 - 3) : 4 + 99] - 100
= 2 . [4 : 4 + 99] - 100
= 2 . [1 + 99] - 100
= 2 . 100 - 100
= 200 - 100
= 100
c) | -5 + 9 | + ( -29 + 5 )
= 4 + (-24)
= -20
a)19+19.99-25.4
=19.999+1)-100
=19.100-100
=100.(19-1)
=100.18
=1800
b)2.[(7-3^3:3^2):2^2+99]-100
=2.[(7-3):4+99]-100
=2.[4:4+99]-100
=2.[1+99]-100
=2.100-100
=200-100
=100
c)|-5+9|+(-29+5)
=|4|+(-24)
=4+(-24)
=-20

\(-8.4+19=-32+19=-13\)
\(-11.3-28=-33-28=-61\)
\(4.\left(-15\right)-18=-60-18=-78\)
\(19-4.\left(-12\right)=19+48=67\)
\(-25.\left(-3\right)-54=75-54=21\)
\(-16-7.\left(-4\right)+24\div\left(-8\right)=-16+28-3=9\)
\(15\div\left(-3\right)+30-7.\left(-3\right)=-5+30+21=46\)
\(-48\div\left(-4\right)+15.\left(-5\right)=12-75=-63\)
\(-29+65\div\left(-5\right)+23=-29-13+23=-19\)
\(15\div\left(-5\right)-17-12.\left(-5\right)=-3-17+60=40\)
\(28.\left(-4\right)-17=-112-17=-129\)
\(-19-7.4=-19-28=-47\)
\(-14.\left(-2\right)-16=28-16=12\)
\(13.\left(-3\right)-65-4.\left(-6\right)=-39-65+24=-80\)
\(-24-8.\left(-6\right)+28=-24+48+28=52\)
Chúc bạn hok tốt!!! tỷ tỷ

31.(-18) + 31.(-81) - 31
= 31.(-18 - 81 - 1)
= 31.(-100) = -3100
-48 + 48.(-78) + 48.(-21) = 48.(-1 - 78 - 21) = 48. (-100) = -4800
-75.(8 - 65) - 65.(75 - 18) = -75.18 + 75.65 - 65.75 + 65.18 = 0
29.(19 - 13) - 19.(29 - 13) = 29.19 - 29.13 - 19.29 + 19.13 = 0
13.(23 + 22) - 3(17 + 28) = 13.25 - 3.45 = (10 + 3).25 - 3.45
= 10 . 25 + 3.25 - 3.45 = 10.25 - 3.(45 - 25)
= 250 - 3.20 = 250 - 60 = 190
(-25).21 . (-2)2.(|3|). (-1)2n + 2 (n \(\in\)N*)
= (-25. 4) . (21.3).1
= -100. 63 = -6300

a) 19 + (29 - 9*37) - (63*9 - 29*99)
= 19 + 29 - 9*37 - 63*9 + 29*99
= 19 + 29(1 + 99) - 9(37 + 63)
= 19 + 29*100 - 9*100
= 19 + 100(29 - 9)
= 19 + 100*20
= 19 + 2000 = 2019
b) \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)
= \(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}\)
= \(\frac{2^6+2^5+2^4+2^3+2^2+2+1}{2^7}\)
= \(\frac{64+32+16+8+4+2+1}{128}\) = \(\frac{127}{128}\)

-8.4+19= -13
-11.3-28=-61
4.(-15)-18=-78
19-4.(-12)=67
-25.(-3)-54=21
-8.4+19=-32+19=-13
-11.3-28=-33-28=-61
4.(-15)-18=-60-18=-78
19-4.(-12)=19-(-48)=67
-25.(-3)-54=75-54=21
-16-7.(-4)+24:(-8)=-16+28-3=12-3=9
15:(-3)+30-7.(-3)=-5+30+21=25+21=46
-48:(-4)+12.(-5)=12-60=-48
-29+65:(-5)+23=-29-13+23=-19
15:(-5)-17-12.(-5)=-3-7+60=-10+60=50
28.(-4)-17=-112-17=-129
-19-7.4=-19-28=-47
-14.(-2)-16=28-16=12
13.(-3)-65-4.(-6)=-39-65+24=-104+24=-80
-24-8.(-6)+28=-24+48+28=24+28=52

Ta có:
\(2\frac{1}{5}+\frac{3}{5}x=\frac{3}{4}\Rightarrow\frac{3}{5}x=\frac{3}{4}-2\frac{1}{5}=-\frac{29}{20}\Rightarrow x=-\frac{29}{20}:\frac{3}{5}=-\frac{29}{12}\)
Vậy \(x=-\frac{29}{12}\)
\(\left(2\frac{1}{5}+\frac{3}{5}x\right)=\frac{3}{4}\)
\(2\frac{1}{5}+\frac{3}{5}x=\frac{3}{4}\)
\(\frac{11}{5}+\frac{3}{5}x=\frac{3}{4}\)
\(\frac{3}{5}x=\frac{3}{4}-\frac{11}{5}=-\frac{29}{20}\)
\(x=\frac{-29}{20}:\frac{3}{5}=-\frac{29}{12}\)

\(6x-65⋮x-8\)
\(\Rightarrow\)\(6\left(x-8\right)-17\)\(⋮x-8\)
Vì \(x-8\)\(⋮x-8\)
nên \(6\left(x-8\right)\)\(⋮x-8\)
Do đó \(17\)\(⋮x-8\)
\(\Rightarrow\)\(x-8\inƯ\left(17\right)\)
\(\Rightarrow\)\(x-8\in\left\{1;-1;17;-17\right\}\)
\(\Rightarrow\)\(x\in\left\{9;7;25;-9\right\}\)
Vậy \(x\in\left\{9;7;25;-9\right\}\)

\(4a+19\text{ là bội của }a+3\)
\(\Leftrightarrow4a+19⋮a+3\)
\(a+3⋮a+3\)
\(\Rightarrow4\left(a+3\right)⋮a+3\)
\(4a+12⋮a+3\)
\(\Rightarrow\left(4a+19\right)-\left(4a+12\right)⋮a+3\)
\(4a+19-4a+12⋮a+3\)
\(31⋮a+3\)
\(\Rightarrow a+3\in\text{Ư}\left(31\right)=\left\{\pm1;\pm31\right\}\)
Ta có bảng : .....................
Tự làm típ nhó !
4a + 19 là bội số của a + 3
\(\Rightarrow4a+19⋮a+3\)
\(4a+12+7⋮a+3\)
\(4\left(a+3\right)+7⋮a+3\)
\(\Rightarrow\hept{\begin{cases}4\left(a+3\right)⋮a+3\\7⋮a+3\end{cases}}\)
\(7⋮a+3\)
\(\Rightarrow a+3\in\)Ư (7) = {-7;-1;1;7}
a + 3 | -7 | -1 | 1 | 7 |
a | -11 | -4 | -2 | 4 |
\(\Rightarrow a\in\left\{-11;-4;-2;4\right\}\)
65-{[(99-19):5+29]:3}
=65-{[80:5+29]:3}
=65-{[16+29]:3}
=65-{45:3}
=65-15
=50
65 - {[(99 - 19) : 5 + 29] :3}
= 65-{[80 :5 +29]:3}
=65-{[16 +29]:3}
=65-{45:3}
=65-15
=50