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\(=4+\dfrac{5}{7}+6,35+5+\dfrac{1}{8}+2,41+1+\dfrac{9}{56}+3,24\)
=1+4+5+1+6,35+2,41+3,24
=11+12=23
1) A = 65% + 6,35 - \(\frac{3}{4}\)
A = \(\frac{65}{100}\)+ \(\frac{635}{100}-\frac{75}{100}\)
A = \(\frac{700}{100}-\frac{75}{100}\)
A = \(\frac{25}{4}\)
1) B = 36% . 2,5 . \(\frac{4}{9}.\frac{5}{48}\)
B = \(\frac{36}{100}.\frac{25}{10}.\frac{4}{9}.\frac{5}{48}\)
B = \(\frac{9}{10}.\frac{5}{108}\)
B = \(\frac{1}{24}\)
a: =-(234,905+36,058)
=-270,963
b: =-34,2*2,16=-73,872
d: =78,74:6,35=12,4
6,35 + 65% - 3/4 = 635% + 65% - 75 %
= 700% - 75%
= 625% = 6,25
Bài làm:
a) \(A=\left|x-0,25\right|\ge0\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|x-0,25\right|=0\Rightarrow x=0,25\)
Vậy GTNN A là 0 khi x = 0,25
b) \(B=\left|x+0,25\right|+1,75\ge1,75\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|x+0,25\right|=0\Rightarrow x=-0,25\)
Vậy GTNN B là 1,75 khi x = -0,25
\(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
\(=\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{2.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{2.\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7.\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)
\(=\frac{2}{7}-\frac{2}{7}\)
\(=0\)
\(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}=\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\)
\(=\frac{2}{7}-\frac{1}{\frac{7}{2}}\)
\(=\frac{2}{7}-\frac{2}{7}=0\)
Study well ! >_<
=>X. 1,7=0,9 . 0,25
=> X . 1,7 = 0,225
=> X =0,225 : 0,17
=> \(\frac{0,225}{0,17}\)
Vậy x= \(\frac{0,225}{0,17}\)
x/0.9=0.25/1.7
x*100/90=25/170
x*17*100/1530=225/1530
=>x*17*100=225
x*1700=225
x=225/1700
x=
http://olm.vn/hỏi-đáp/question/584545.html chờ xí tui thấy cái tên rồi giải cho bài 2
a,\(\frac{5}{3}.\frac{3}{7}+\frac{5}{3}.\frac{5}{7}-\frac{5}{3}\)
=\(\frac{5}{3}.\left(\frac{3}{7}+\frac{5}{7}\right)-\frac{5}{3}\)
= \(\frac{5}{21}\)
-6,35 x 0,25 - 6,35 x 1,75 + 6,35
= - 6,35 x (0,25 + 1,75 - 1)
= -6,35 x (2 - 1)
= -6,35 x 1
= - 6,35
\(-6,35\cdot0,25-6,35\cdot1,75+6,35\)
\(=6,35\left(-0,25-1,75+1\right)\)
\(=6,35\cdot\left(-2+1\right)\)
\(=6,35\cdot\left(-1\right)=-6,35\)