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Bài 1 tự làm!
Bài 2:
a, \(\left(3x-4\right)\left(x-1\right)^3=0\Rightarrow\left[{}\begin{matrix}3x-4=0\\\left(x-1\right)^3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=1\end{matrix}\right.\)
b, \(2^{2x-1}:4=8^3\Rightarrow2^{2x-1}:2^2=2^9\)
\(\Rightarrow2x-1-2=9\Rightarrow2x-3=9\Rightarrow2x-12\Rightarrow x=6\)
c, Đề chưa rõ
d, \(\left(x+2\right)^5=2^{10}\Rightarrow\left(x+2\right)^5=4^5\Rightarrow x+2=4\Rightarrow x=2\)
e, \(\left(3x-2^4\right).7^3=2.7^4\Rightarrow3x-2^4=2.7^4:7^3\Rightarrow3x-16=2.7=14\)
\(\Rightarrow3x=14+16=30\Rightarrow x=\dfrac{30}{3}=10\)
f, \(\left(x+1\right)^2=\left(x+1\right)^0\Rightarrow\left(x+1\right)^2=1\) (vì x0 = 1)
\(\Rightarrow x+1=1\Rightarrow x=0\)
\(a,60-3.\left(x-2\right)=51\)
\(3.\left(x-2\right)=60-51\)
\(3.\left(x-2\right)=9\)
c \(x-2=9:3\)
\(x-2=3\)
\(x=3+2\)
\(x=5\)
\(b,541+\left(218-x\right)=725\)
\(218-x=725-541\)
\(218-x=184\)
\(x=218-184\)
\(x=34\)
\(c,3.\left(5x-13\right)=3^4\)
\(3.\left(5x-13\right)=81\)
\(5x-13=81:3\)
\(5x-13=27\)
\(5x=27+13\)
\(5x=40\)
\(x=8\)
\(d,\left(2x-7\right)-\left(x+135\right)=0\)
\(2x-7-x-135=0\)
\(x-142=0\)
\(x=0+142\)
\(x=142\)
1)a)(x-5)6-(x-5)4=0 =>(x-5)4.((x-5)2-1)=0
=>(x-5)6=0 hoặc ((x-5)2-1)=0
làm nốt nhé ko có thời gian
b)x15=x2 =>x15-x2=0 =>x2.(x13-1)=0
lại xét như trên
2)a) xét 2s=2+22+23+.....+251
2s-s=(2+22+23+.....+251)-(1+2+22+.....250)
s=250-1
b) xét 25m=53+55+57+.....+5101
25m-m=5101-5
m=(5101-5)/24
\(3^x+3^{x+1}+3^{x+2}=3900\)
\(3^x+3^x.3+3^x.9=3900\)
\(3^x\left(1+3+9\right)=3900\)
\(3^x.13=3900\)
\(3^x=3900:13\)
\(3^x=300\)
5x + 5 x+1 = 5x + 5x . 5 = 5x .(1+5) = 725
=> 5x = 725 : 6 = \(\frac{725}{6}\)
mà 5x \(\in\)Z
=> x ko có giá trị
5^x+5^x+5=725
5^x.(1+5)=725
5^x=725:6(vo li)
=>xthuoc rong