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a)4.(x+3)-(2x-12)=x-(-11+4)
4x+12-2x+12=x+11-4
2x+24=x+7
2x-x=-24+7
x=-17
b)-(4x-13)+(5x-4)=-3-(-15+7)
-4x+13+5x-4=-3+15-7
(-4x+5x)+13-4=12-7
x+9=5
x=-4
c)(5x-3)-(-2x+4)=6x-12
5x-3+2x-4=6x-12
5x+2x-6x=3+4-12
x=-5
d)(15x+20)-(9x-3)=5x-(-12)
15x+20-9x+3=5x+12
15x-9x-5x=-20-3+12
x=-11
e,(7x+14)+(3x-8)=-(-9x+3)
7x+14+3x-8=9x-3
7x+3x-9x=-14+8-3
x=-9
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a, 117 - \(x\) = 28 - (-7)
117 - \(x\) = 28 + 7
117 - \(x\) = 35
\(x\) = 117 - 35
\(x\) = 82
b, \(x\) - (-38 - 2\(x\)) = (-3) - 8 + 2\(x\)
\(x\) + 38 + 2\(x\) = - 11 + 2\(x\)
3\(x\) + 38 = - 11 + 2\(x\)
3\(x\) - 2\(x\) = - 11 - 38
\(x\) = - 49
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a: =>x+38+2x=-3-8+2x
=>3x+38=2x-11
=>x=-49
b: \(\Leftrightarrow65+x-15-5x=12-5x\)
=>-4x+50=-5x+12
=>x=-38
c: \(\Leftrightarrow3x+12-7x+21=-3-5x-2=-5x-5\)
=>-4x+33=-5x-5
=>x=-38
d: \(\Leftrightarrow-123+2x+23=x-120\)
=>2x-100=x-120
=>x=-20
e: =>-45+25+5x=16-x
=>5x-20=-x+16
=>6x=36
=>x=6
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a) -(3x - 5) - (-5x - 7 ) = 6
-3x + 5 + 5x + 7 = 6
( -3 + 5 )x + 5 + 7 = 6
2x + 12 = 6
2x = -6
x = -3
c) -5x - 17 = -2x + 4
-5x + 2x = 4 + 17
-3x = 21
x = -7
a) -(3x-5)-(-5x-7) =6
-3x+5 +5x+7 =6
(-3x+5x)+(5+7)=6
[(-3+5)x]+ 12 =6
2x + 12 =6
2x =6-12
2x =-6
x=-6:2
x=-3
b) (-5x-12)-(x+3) =1
-5x-12 - x-3 =1
(-5x-x) -(12-3)=1
(-5x-1x) - 9 =1
[(-5-1)x] - 9 =1
-6x-9=1
-6x=1+9
-6x=10
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5x - ( - 3 + 4) = 12 - x
5x - 1 = 12 -x
5x +x = 12 + 1
6x = 13
x = 13/6
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a) Ta có:
3x + 2012 = 2015
3x = 2015 - 2012
3x = 3
x = 3 : 3
x = 1
Vậy x = 1
b) Ta có:
5x - 12 = 32 .52
5x - 12 = 468
5x = 480
x = 96
Vậy x = 96
c) Ta có:
2012 - (2013 - x) = 12
2013 - x = 2000
x = 13
Vậy x = 13
d) Ta có:
2002 : [12+(2x-20)] = 91
12+(2x-20) = 22
2x-20 = 10
2x = 30
x = 15
Vậy x = 15
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( 12 - 5x )3 = 343
( 12 - 5x )3 = 73
\(\Rightarrow\)12 - 5x = 7
5x = 12 -7
5x = 5
\(\Rightarrow\)x = 1
Hk tốt
\(\left(12-5x\right)^3=343\Leftrightarrow\left(12-5x\right)^3=7^3\)
\(\Leftrightarrow12-5x=7\Leftrightarrow5x=12-7\)
\(\Leftrightarrow5x=5\Leftrightarrow x=5:5\)
\(\Leftrightarrow x=1\)
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1. \(3-|2x+1|=-5\)
\(\Rightarrow|2x+1|=8\)
\(\Rightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=7\\2x=-9\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{9}{2}\end{cases}}\)
Vậy \(x\in\left\{\frac{7}{2};-\frac{9}{2}\right\}\)
2.\(12+|3-x|=9\)
\(\Rightarrow|3-x|=-3\)
Mà \(|3-x|\ge0\forall x\)
\(\Rightarrow\)Vô lí
Vậy không có x
3.\(|x+9|=12+\left(-9\right)+2\)
\(\Rightarrow|x+9|=5\)
\(\Rightarrow\orbr{\begin{cases}x+9=5\\x+9=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-4\\x=-14\end{cases}}\)
Vậy \(x\in\left\{-4;-14\right\}\)
4.\(5x-16=40+x\)
\(\Rightarrow5x-x=40+16\)
\(\Rightarrow4x=56\)
\(\Rightarrow x=14\)
Vậy \(x=14\)
5.\(5x-7=-21-2x\)
\(\Rightarrow5x+2x=-21+7\)
\(\Rightarrow7x=-14\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
6.\(\left(2x-1\right)\left(y-2\right)=12\)
Vì \(x,y\inℤ\)nên \(2x-1;y-2\inℤ\)
\(\Rightarrow2x-1;y-2\inƯ\left(12\right)=\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\right\}\)
Ta có bảng : (em tự xét bảng nhé)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x-36\right):18=12\)
\(x-36=12.18\)
\(x-36=216\)
\(x=252\)
vậy \(x=252\)
\(5x-3=3x-11\)
\(5x-3x=-11+3\)
\(2x=-8\)
\(x=-4\)
vậy \(x=-4\)
\(3x+5x=16\)
\(8x=16\)
\(x=2\)
vậy \(x=2\)
\(2\left(x+1\right)=10\)
\(x+1=5\)
\(x=4\)
vậy \(x=4\)
k nha Pham Tuyet Nhung
1.=> x-36 = 216 = > x = 216 +36 =252
2. =>2x = -8 = > x= -4
3.8 x = 16 = > x = 2
4 . => x= 10 -1 = 9
ok có j ko hiểu hỏi riêng nha