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\(\frac{5}{6}\cdot x+\frac{2}{3}\cdot\left(\frac{3}{5}\cdot x-\frac{6}{5}\right)=\frac{2}{9}-\frac{1}{2}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{3}\cdot\frac{3}{5}\cdot x-\frac{2}{3}\cdot\frac{6}{5}=-\frac{5}{18}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{5}\cdot x-\frac{4}{5}=-\frac{5}{18}\)
\(\Rightarrow x\cdot\left(\frac{5}{6}+\frac{2}{5}\right)=-\frac{5}{18}+\frac{4}{5}\)
\(\Rightarrow x\cdot\frac{37}{30}=\frac{47}{90}\)
\(\Rightarrow x=\frac{47}{90}\div\frac{37}{30}\)
\(\Rightarrow x=\frac{47}{111}\)
Vậy \(x=\frac{47}{111}\)
\(\left(\frac{2}{3}x-\frac{1}{2}\right)\cdot\left(-\frac{2}{3}\right)+\frac{1}{5}=-\frac{3}{4}\)
=> \(\left(\frac{2}{3}x-\frac{1}{2}\right)\cdot\left(-\frac{2}{3}\right)=-\frac{3}{4}-\frac{1}{5}=-\frac{19}{20}\)
=> \(\frac{2}{3}x-\frac{1}{2}=-\frac{19}{20}:\left(-\frac{2}{3}\right)=-\frac{19}{20}\cdot\left(-\frac{3}{2}\right)=\frac{57}{40}\)
=> \(\frac{2}{3}x=\frac{57}{40}+\frac{1}{2}=\frac{77}{40}\)
=> \(x=\frac{231}{80}\)
Cái phần .-2/3 tức là . (-2/3) à hay sao vậy.Nên sửa lại đề
1) = \(\frac{3}{5}\)
2) =\(\frac{6}{7}\)
3)\(\frac{9}{13}\)
4)\(\frac{4}{13}\)
Bài 1:
a,\(0,75+\frac{9}{17}-1\frac{4}{5}-\frac{26}{17}-2\frac{4}{5}\)
\(=\frac{3}{4}+\left(\frac{9}{17}-\frac{26}{17}\right)-\left(1\frac{4}{5}+2\frac{4}{5}\right)\)
\(=\frac{3}{4}-1-\frac{23}{5}\)
\(=\frac{15}{20}-\frac{20}{20}-\frac{92}{20}=\frac{-97}{20}\)
Bài 2:
a, \(\left(2x+\frac{3}{4}\right)-\frac{10}{3}=\frac{-13}{3}\)
\(2x+\frac{3}{4}=\frac{-13}{3}+\frac{10}{3}\)
\(2x+\frac{3}{4}=-1\)
\(2x=-1-\frac{3}{4}\)
\(2x=\frac{-7}{4}\)
x = -7/8
b, 3,2x - 2,7x + 8,5 = 6
x(3,2 - 2,7) = -2,5
0,5x = -2,5
x = -5
\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^x\)
\(\Rightarrow\frac{4.4^5}{3.3^5}.\frac{6.6^5}{2.2^5}=2^x\)
\(\Rightarrow\frac{4^6}{3^6}.\frac{6^6}{2^6}=2^x\)
\(\Rightarrow\frac{4^6.6^6}{3^6.2^6}=2^x\)
\(\Rightarrow\frac{\left(4.6\right)^6}{\left(3.2\right)^6}=2^x\)
\(\Rightarrow\frac{24^6}{6^6}=2^x\)
\(\Rightarrow4^6=2^x\)
\(\Rightarrow\left(2^2\right)^6=2^x\)
\(\Rightarrow2^{2.6}=2^x\)
\(\Rightarrow2^{12}=2^x\)
\(\Rightarrow x=12\)
\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^x.\)
\(\Rightarrow\frac{4.4^5}{3.3^5}.\frac{6.6^5}{2.2^5}=2^x\)\(\Rightarrow\frac{4^6.6^6}{3^6.2^6}=2^x\)
\(\Rightarrow\frac{2^6.2^6.2^6.3^6}{3^6.2^6}=2^x\)\(\Rightarrow2^6.2^6=2^x\)
\(\Rightarrow2^{12}=2^x\Leftrightarrow x=12\)
a) 32.x+2=1342176728
32.x=134217728-2
32.x=134217726
x=134217726:32
x=4194303,938
1: \(\Leftrightarrow3\left|x-7\right|-48\left|x+2\right|=3x-8\)
TH1: x<-2
Pt sẽ là 3(7-x)-48(-x-2)=3x-8
=>21-3x+48x+96=3x-8
=>45x+117=3x-8
=>42x=-125
=>x=-125/42(nhận)
TH2: -2<=x<7
Pt sẽ là 3(7-x)-48(x+2)=3x-8
=>21-3x-48x-96=3x-8
=>-51x-75=3x-8
=>-48x=67
=>x=-67/48(nhận)
TH3: x>=7
Pt sẽ là 3(x-7)-48(x+2)=3x-8
=>3x-21-48(x+2)=3x-8
=>48(x+2)=-21+8=-13
=>x+2=-13/48
=>x=-109/48(loại)
3: =>|3x-5|=|x-7|
=>3x-5=x-7 hoặc 3x-5=-x+7
=>2x=-2 hoặc 4x=12
=>x=3 hoặc x=-1
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