
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


35*12+65*13=420+845=1265
53*39+39*47-53*21-47*21=1800

\(R=\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+...+\frac{2006.2006}{2005.2007}\)
\(R=\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+...+\frac{2006^2}{2005.2007}\)
\(R=\frac{1.3+1}{1.3}+\frac{2.4+1}{2.4}+\frac{3.5+1}{3.5}+...+\frac{2005.2007+1}{2005.2007}\)
\(R=1+\frac{1}{1.3}+1+\frac{1}{2.4}+1+\frac{1}{3.5}+...+1+\frac{1}{2005.2007}\)
\(R=\left(1+1+...+1\right)+\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{2005.2007}\right)+\left(\frac{1}{2.4}+\frac{1}{4.6}+...+\frac{1}{2004.2006}\right)\)
( có 2005 số 1)
\(R=2005+\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2005}-\frac{1}{2007}\right)\)
\(+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{2004}-\frac{1}{2006}\right)\)
\(R=2005+\frac{1}{2}.\left(1-\frac{1}{2007}\right)+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{2006}\right)\)
\(R=2005+\frac{1}{2}\cdot\frac{2006}{2007}+\frac{1}{2}\cdot\frac{501}{1003}\)
\(R=2005+\frac{1003}{2007}+\frac{501}{2006}\)
...
đến đây bn tự tính típ nha!




Ta có : \(A=\frac{5}{3.9}+\frac{5}{9.15}+\frac{5}{5.21}+.....+\frac{5}{63.69}\)
\(\Rightarrow A=\frac{5}{6}\left(\frac{6}{3.9}+\frac{6}{9.15}+\frac{6}{15.21}+......+\frac{6}{63.69}\right)\)
\(\Rightarrow A=\frac{5}{6}\left(\frac{1}{3}-\frac{1}{9}+\frac{1}{9}-\frac{1}{15}+.....+\frac{1}{63}-\frac{1}{69}\right)\)
\(\Rightarrow A=\frac{5}{6}\left(\frac{1}{3}-\frac{1}{69}\right)\)
\(\Rightarrow A=\frac{5}{6}.\frac{22}{69}=\frac{55}{207}\)

\(53.39+47.39+53.21+47.21\)
\(=53\left(39+21\right)+47\left(39+21\right)\)
\(=53.60+47.60\)
\(=60\left(53+47\right)\)
\(=60.100\)
\(=6000.\)
Theo Thắng làm như sau : 53.39+47.39+53.21+47.2153.39+47.39+53.21+47.21
=53(39+21)+47(39+21)=53(39+21)+47(39+21)
=53.60+47.60=53.60+47.60
=60(53+47)=60(53+47)
=60.100=60.100
=6000.
I don't now
or no I don't
..................
sorry
\(2067+1833-315-1085\)
\(=2500\)
\(4024036-4024035\)
\(1\)