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a) \(125^3:25^4=\left(5^3\right)^3:\left(5^2\right)^4=5^9:5^8=5\)
b) \(\left(10^3+10^4+125^2\right):5^3\)
\(=\left[\left(5.2\right)^3+\left(5.2\right)^4+\left(5^3\right)^2\right]:5^3\)
\(=\left(5^3.2^3+5^4.2^4+5^6\right):5^3\)
\(=\frac{5^3.2^3}{5^3}+\frac{5^4.2^4}{5^3}+\frac{5^6}{5^3}\)
\(=2^3+5.2^4+5^3=213\)
c) \(24^4:3^4-32^{12}:16^{12}\)
\(=\left(3.8\right)^4:3^4-\left(16.2\right)^{12}:16^{12}\)
\(=3^4.8^4:3^4-2^{12}.16^{12}:16^{12}\)
\(=8^4-2^{12}=\left(2^3\right)^4-2^{12}=2^{12}-2^{12}=0\)
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\(5^{5\left(2x+1\right)-3}=25^{11}\)
\(5^{5\left(2x+1\right)-3}=\left(5^2\right)^{11}\)
\(5^{5\left(2x+1\right)-3}=5^{22}\)
\(\Rightarrow5\left(2x+1\right)-3=22\)
\(\Rightarrow5\left(2x+1\right)=22+3\)
\(\Rightarrow5\left(2x+1\right)=25\)
\(\Rightarrow2x+1=25\div5\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4\div2\)
\(\Rightarrow x=2\)
k mk nha !
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a)25.4:32=25.22:25=25+2-5=22=4
b)3.27:34=3.33:34=34:34=1
c)(29.16+29.32):210
=29.(16+32):210
=48:210-9
=48:2
=24
d)Bạn chữa lại dề nha
(34.57-92.21):35
=(34.57-34.22):35
=34.(57-22):35
=34.35:35
=34
=81
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a)410x220x830 b)56x53+32x33
=(22)10x220x(23)30 =56+3+32+3
=220x220x290 =59+35
=220+20+90 =1953125+243
=2130 =1953368.
c)13+23+33+43+53 d)225:324
=1+8+27+64+125 =225 :(25)4
=9+27+64+125 =225:220
=36+64+125 =225-20
=100+125 =25
=225
a)\(\left(2^2\right)^{10}.2^{20}.\left(2^3\right)^{30}=2^{20}.2^{20}.2^{90}=2^{130}\)
b)\(5^{6+3}+3^{2+3}=5^9+3^5\)
c)\(1^3+2^3+3^3+4^3+5^3=\left(1+2+3+4+5\right)^2=15^2=225\)
d)\(2^{25}:32^4=2^{25}:\left(2^5\right)^4=2^{25}:2^{20}=2^{25-20}=2^5=32\)
53 : 25 - 43 : 16 + 25 : 32
= 53 : 52 - 43 : 42 + 25 : 25
= 5 - 4 + 1
= 1 + 1
= 2