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a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
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a, 2(x - 51) = 2.23 + 20
=> 2(x - 51) = 2.8 + 20
=> 2(x - 51) = 16 + 20
=> 2(x - 51) = 36
=> x - 51 = 18
=> x = 69
vậy_
b, 32(x + 4) - 52 = 5.22
=> 9(x + 4) - 25 = 5.4
=> 9x + 36 - 25 = 29
=> 9x + 9 = 29
=> 9x = 20
=> x = 20/9
vậy_
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a. Ta có : 2,5 < 5,2 => 2,53 < 5,23
b. Ta có : 45 = 1024 ; 54 = 625
Vì 1024 > 625 => 45 > 54
\(a.2.5^3va5.2^3\)
\(2.5^3=2.125=250;5.2^3=5.8=40\)
Vì \(250>40\)
\(\Rightarrow2.5^3>5.2^3\)
\(b.4^5va5^4\)
\(4^5=1024;5^4=625\)
Vì \(1024>625\)
\(\Rightarrow4^5>5^4\)
\(c.2^8va2.5^3\)
\(2^8=256;2.5^3=2.125=250\)
Vì \(256>250\)
\(\Rightarrow2^8>2.5^3\)
2.Tìm x:
\(a.2^n+4.2^n=5.2^5\)
\(2^n\left(1+4\right)=5.32\)
\(2^n.5=160\)
\(2^n=160:5\)
\(2^n=32\)
\(2^n=2^5\)
\(\Rightarrow n=5\)
\(b.3^4.3^n:9=3^7\)
\(3^4.3^n:3^2=3^7\)
\(3^4.3^n=3^7.3^2\)
\(3^4.3^n=3^{7+2}\)
\(3^4.3^n=3^9\)
\(3^n=3^9:3^4\)
\(3^n=3^{9-4}\)
\(3^n=3^5\)
\(\Rightarrow n=5\)
\(c.6.2^n+3.2^n=9.2^n\)
\(2^n\left(6+3\right)=9.2^n\)
\(2^n.9=9.2^n\)
\(\Rightarrow2^n=9:9\)
\(\Rightarrow2^n=1\)
\(\Rightarrow2^n=2^0\)
\(\Rightarrow n=0\)
Chúc bạn học tốt!
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a: \(=\dfrac{\left(5\cdot2^6+2^6\cdot3^2-2^6\cdot3\right)}{2^6}=5+9-3=2+9=11\)
b: \(=\dfrac{600}{450:\left[450-4\cdot125+8\cdot25\right]}\)
\(=\dfrac{600}{450:150}=\dfrac{600}{3}=200\)
c: \(=1500-\left\{125\cdot8-11\cdot\left(49-5\cdot8+8\cdot0\right)\right\}\)
\(=1500-\left\{1000-99\right\}=1500-901=599\)
a ,
5.22 +( x + 3) = 5^2
TH1 : nếu là : 5^2
ta có :
5.22 +( x + 3) = 5^2
(=) 20 + ( x + 3 ) = 5^2
(=) x + 3 = 32
(=) x = 29
a) 5.22 + (x + 3) = 52
<=> 20 + x + 3 = 25
<=> x + 3 = 5
<=> x = 2
b) 23 + (x - 32) = 53 - 43
<=> 8 + (x - 9) = 61
<=> x - 1 = 61
<=> x = 62