
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

giải phương trình \(\frac{29-x}{21}\)+\(\frac{27-x}{3}\)+\(\frac{25-x}{25}\)+\(\frac{21-x}{29}\)= -5


Ta có \(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)
=> \(\frac{9}{25}x\left(1+\frac{3}{5}+1\right)+18\left(\frac{3}{5}+1\right)=x\)
=> \(\frac{117}{125}x+28,8=x\)
=> \(x-\frac{117}{125}x=28,8\)
=> \(\frac{8}{125}x=28,8\)
=> x = 450
Vậy x = 450
\(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)
\(x\left(\frac{9}{25}+\frac{9}{25}+\frac{9}{25}\right).\frac{3}{5}+\frac{3}{5}.18+18=x\)
\(x.\frac{3}{5}\left(\frac{27}{25}+18\right)+18=x\)
\(x.\frac{3}{5}\left(\frac{27}{25}+\frac{450}{25}\right)+18=x\)
\(x.\frac{3}{5}.\frac{477}{25}+18=x\)
\(x.\frac{1431}{125}+\frac{2250}{125}=x\)
\(x.\frac{3681}{125}=x\)
vậy chac tui làm sai rồi

a) \(x-25\%x=0,5\)
\(\dfrac{3}{4}x=0,5\)
x = \(\dfrac{2}{3}\)
b) \(\left(50\%x+5\dfrac{1}{4}\right).\dfrac{-2}{3}=2\dfrac{5}{6}\)
\(\left(0,5x+\dfrac{21}{4}\right)=\dfrac{-17}{4}\)
\(0,5x=\dfrac{-19}{2}\)
x = -19
c) \(\left(1\dfrac{1}{3}-25\%-\dfrac{5}{12}\right)+2x=1,5:\dfrac{3}{5}\)
\(\dfrac{2}{3}+2x=\dfrac{5}{2}\)
\(2x=\dfrac{11}{6}\)
x= \(\dfrac{11}{12}\)

\(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{26}{25}-\dfrac{17}{25}=\dfrac{9}{25}\) \(\Leftrightarrow\left\{{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=\dfrac{-3}{5}\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{5}-\dfrac{1}{5}\\x=\dfrac{-3}{5}-\dfrac{1}{5}\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{5}\\x=\dfrac{-4}{5}\end{matrix}\right.\)
vậy \(x=\dfrac{2}{5};x-\dfrac{-4}{5}\)

mk sắp phải đi học rồi các bạn giúp mình với có đc ko mk nhớ sẽ đền đáp công ơn của bạn

525 x 5x-1 = 525
5x-1 = 525 : 525
5x+1 = 1
Vì bất kì luỹ thừa nào mũ 0 đều bằng 1
Nên => x = 1 (vì 1-1 = 0 mà 50 = 1 => x=1)
\(5^{25}\times5^{x+1}=5^{25}\)
\(5^{x+1}=5^{25}\div5^{25}\)
\(5^{x+1}=1\)
\(5^x\times5=5^0\)
\(5^x=5^0\div5\)
\(\Rightarrow5^x\in\varnothing\)
\(\Rightarrow x\in\varnothing\)
Vậy \(x\in\varnothing\)

5x+1- 5x=100.2529
5x.(5-1) = 100.2529
5x.4=100.2529
5x=100.2529: 4
5x=25.2529
5x=2530
5x= (52)30
5x=560
=> x =60
#yêuToán
5x + 1 - 5x = 100.2529
=> 5x.5 - 5x = 4.52.(52)29
=> 5x(5 - 1) = 4.52.558
=> 5x .4 = 4.560
=> 5x = 4.560 : 4
=> 5x = 560
=> x = 60

a) \(3,54.73+0,23.25+3,54.27+0,17.25\)
\(=3,54.\left(73+27\right)+25.\left(0,23+0,17\right)\)
\(=3,54.100+25.0,4\)
\(=354+10\)
\(=364\)
b) \(12,25:\left(5\frac{9}{20}-4\frac{1}{5}\right)+2,4.3\)
\(=12,25:\left(\frac{109}{20}-\frac{21}{5}\right)+7,2\)
\(=12,25:1,25+7,2\)
\(=9,8+7,2\)
\(=17\)
a,3, 54 x 73 + 0,23 x 25 + 3,54 x 27 + 0,17 x 25
= 3,54 x 73 + 3,54 x 27 + 0,23 x 25 + 0,17 x 25
= 3,54 x(73+27) + 25 x (0,23+0,17)
= 3,54 x 100 + 25 x 0,4
= 3,54 x 100 + 10
= 35,4 x 10 + 10
= 10 x (35,4+1)
= 10 x 36,4
= 364
b,12 , 25 : ( \(5\frac{9}{20}-4\frac{1}{5}\)) + 2 , 4 . 3
= 12 , 25 : ( 109 / 20 - 105 /20 ) + 7 , 2
= 12 , 25 : 1/5 + 7, 2
= \(\frac{1225}{1000}\): \(\frac{3}{2}\) + \(\frac{36}{5}\)
= ( bạn tính nốt nha )
Chúc bạn học tốt !
5x=25
=>\(x=\frac{25}{5}\)
=>x=5
5\(x\) = 25
\(x=25:5\)
\(x=5\)
Vậy \(x\) = 5