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a, \(\left(301\right)^2=\left(300+1\right)^2=300^2+2.300.1+1^2\)
=90000+6000+1=90601
b,\(499^2=\left(500-1\right)^2=500^2-2.500.1+1^2\)
=10000-10000+1=1
a) 3012 = ( 300 + 1 )2 = 3002 + 2.300.1 + 12 = 90601
b) 4992 = ( 500 - 1 )2 = 5002 - 2.500.1 + 12 = 249001
c) 68.72 = ( 70 - 2). ( 70 + 2) = 702 - 42 = 4900 - 16 = 4884
Bài1:
\(\left(3+xy^2\right)^2=81+6xy^2+x^2y^4\)
Các câu sau tương tự
Bài2:
\(a,\left(4x^2+4xy+y^2\right)\)
=\(\left(2x+y\right)^2\)
b)\(9m^2+n^2-6mn=\left(3m-n\right)^2\)
c)\(16a^2+25b^2+40ab=\left(4a+5b\right)^2\)
d)\(x^2-x+\dfrac{1}{4}=\left(x-\dfrac{1}{2}\right)^2\)
Bài3:
\(a,301^2=\left(300+1\right)^2=900+600+1=1501\)
b/\(499^2=\left(500-1\right)^2=2500-1000+1=1501\)
c/\(68.72=\left(70-2\right)\left(70+2\right)=70^2-2^2=4900-4=4896\)
Giải:
a) \(301^2\)
\(=\left(300+1\right)^2\)
\(=300^2+2.300.1+1^2\)
\(=90000+600+1\)
\(=90601\)
b) \(499^2\)
\(=\left(500-1\right)^2\)
\(=500^2-2.500.1+1^2\)
\(=250000-1000+1\)
\(=249001\)
c) \(68.72\)
\(=\left(70-2\right).\left(70+2\right)\)
\(=70^2-2^2\)
\(=4900-4\)
\(=4896\)
Chúc bạn học tốt!!!
a) = (68+32)2 = 104
b) = (x+1)2 - y2 = (x+1-y)(x+1+y)
thay vào mà tính
Trả lời:
\(51^2=\left(50+1\right)^2\)
\(=50^2+2\times50\times1+1^2\)
\(=2500+100+1\)
\(=2601\)
\(301^2=\left(300+1\right)^2\)
\(=300^2+2\times300\times1+1^2\)
\(=90000+600+1\)
\(=90601\)
\(99^2=\left(100-1\right)^2\)
\(=100^2-2\times100+1\)
\(=10000-200+1\)
\(=9801\)
Học tốt
a) 342+662+68.66=342+662+2.34.66
=(34+66)2=1002=10000
b)742+242-48.74=742+242-2.24.74
=(74-24)2=502=2500
\(\text{a) }301^2\\ =\left(300+1\right)^2\\ =300^2+2\cdot300\cdot1+1^2\\ =90000+600+1\\ =90601\\ \)
\(\text{b) }499^2\\ =\left(500-1\right)^2\\ =500^2-2\cdot500\cdot1+1^2\\ =250000-1000+1\\ =249001\\ \)
\(\text{c) }68\cdot72\\ =\left(70-2\right)\left(70+2\right)\\ =70^2-2^2\\=4900-4\\ =4896\\ \)
a) \(301^2\)
\(=\left(300+1\right)^2\)
\(=300^2+600+1\)
\(=90601\)
b) \(499^2\)
\(=\left(500-1\right)^2\)
\(=500^2-1000+1\)
\(=249001\)
c) \(68\cdot72\)
\(=\left(70-2\right)\left(70+2\right)\)
\(=70^2-2^2\)
\(=4896\)