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a) \(\left(4x-1\right)^2-\left(3x+2\right)\left(3x-2\right)=\left(7x-1\right)\left(x+2\right)+\left(2x+1\right)^2-\left(4x^2+7\right)\)(1)
\(\Leftrightarrow\left(16x^2-8x+1\right)-\left(9x^2-4\right)=\left(7x^2+14x-x-2\right)+\left(4x^2+4x+1\right)-\left(4x^2+7\right)\)
\(\Leftrightarrow16x^2-8x+1-9x^2+4=7x^2+13x-2+4x^2+4x+1-4x^2-7\)
\(\Leftrightarrow7x^2-8x+5=7x^2+17x-8\)
\(\Leftrightarrow7x^2-8x-7x^2-17x=-8-5\)
\(\Leftrightarrow-25x=-13\)
\(\Leftrightarrow x=\dfrac{13}{25}\)
Vậy tập nghiệm phương trình (1) là \(S=\left\{\dfrac{13}{25}\right\}\)
Bài 2:
\(=\dfrac{x^2\left(x^2+4\right)-2x\left(x^2+4\right)}{x^2+4}=x^2-2x\)
Bài 1:
a: \(=\left(\dfrac{2}{3}:\dfrac{-1}{9}\right)\cdot x^4y^2z^6=-6x^4y^2z^6\)
b: \(=-12x^8-21x^5\)
c: =x^3+8
d: \(=125x^3-75x^2+15x-1\)
1: \(\Leftrightarrow-4x^2+3x-4x^2+8x=10\)
=>-8x^2+11x-10=0
=>\(x\in\varnothing\)
2: \(\Leftrightarrow5x^2-15x+5+x-5x^2=x-2\)
=>-14x+5=x-2
=>-15x=-7
=>x=7/15
3: \(\Leftrightarrow12x^2-12x^2+20x=10x-17\)
=>10x=-17
=>x=-17/10
4: \(\Leftrightarrow4x^2-2x+3-4x^2+20x=7x-3\)
=>18x+3=7x-3
=>11x=-6
=>x=-6/11
5: \(\Leftrightarrow-3x+15+5x-5+3x^2=4-x\)
\(\Leftrightarrow3x^2+2x+10-4+x=0\)
=>3x^2+3x+6=0
hay \(x\in\varnothing\)
1) \(-4x^5\left(x^3-4x^2+7x-3\right)\)
\(=-4x^8+16x^7-28x^6+12x^5\)
2) \(3x^4\left(-2x^3+5x^2-\dfrac{2}{3}x+\dfrac{1}{3}\right)\)
\(=-6x^7+15x^6-2x^5+x^4\)
3) \(-5x^2y^4\left(3x^2y^3-2x^3y^2-xy\right)\)
\(=-15x^4y^7+10x^5y^6+5x^3y^5\)
4) \(4x^3y^2\left(-2x^2y+4x^4-3y^2\right)\)
\(=-8x^5y^3+16x^7y^2-12x^3y^4\)
a) 4x2 - 12x + 5
= 4x2 - 2x - 10x + 5
= (4x2 - 2x) + (-10x + 5)
= 2x(x - 2) - 5 ( x - 2)
= (x - 2) (2x - 5)
còn lại tương tự nha
ok mk nha!!! 5547565876876876345645645666575676575688768898778978234532344543
ý lộn mk làm lại:
4x2 - 12x + 5
= 4x2 - 2x - 10x + 5
= 2x(2x - 1) - 5(2x - 1)
= (2x - 1) (2x - 5)
ok mk nhé!!!! 546465765876876876769789785653645645234634634457756756
x^3 - 7x - 6 = x^3 + x^2 - x^2 - 6x - x - 6 = (x^3 + x^2) - (x^2 + x) - (6x + 6)
= x^2(x + 1) - x(x + 1) - 6(x + 1) = (x + 1)(x^2 - x - 6) = (x + 1)(x^2 - 3x + 2x - 6)
= (x + 1){(x^2 - 3x) + (2x - 6)} = (x + 1){(x(x - 3) + 2(x - 3)}
= (x + 1)(x - 3)(x + 2)
câu c
\(C=\left(2x-1\right)^3+\left(2x-1\right)\left(4x^2+2x+1\right)\)
\(C=\left(2x-1\right)\left[\left(2x-1\right)^2+\left(4x^2+2x+1\right)\right]\)
\(C=\left(2x-1\right)\left[\left(4x^2-4x+1\right)+\left(4x^2+2x+1\right)\right]\)
\(C=2\left(2x-1\right)\left[4x^2-x+1\right]\)
`-4x^5 (x^3-4x^2+7x-3)`
`=-4x^8 + 16x^7 - 28x^6 +12x^5`