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4x + 3 + 4x = 1040
4x . 43 + 4x . 1 = 1040
4x ( 43 + 1 ) = 1040
4x . 65 = 1040
4x = 1040 : 65 = 16 = 42
Vậy x = 2
\(4^{x+3}+4^x=1040\)
\(\Leftrightarrow4^x\left(1+4^3\right)=1040\)
\(\Leftrightarrow4^x.65=1040\)
\(\Leftrightarrow4^x=16\)
\(\Leftrightarrow x=2\)


4x + 43 + 4x= 1040
4x . ( 43 + 1 ) = 1040
4x . 65 = 1040
4x = 1040 : 65
4x = 16
4 x = 42
suy ra x = 2
vậy x = 2

\(a)5\left(3-2x\right)+5\left(x-4\right)=6-4x\)
\(\Leftrightarrow5\left(3-2x+x-4\right)=6-4x\)
\(\Leftrightarrow5\left(-x-1\right)=6-4x\)
\(\Leftrightarrow-5x-5=6-4x\)
\(\Leftrightarrow-x=11\Leftrightarrow x=-11\)
Vậy \(x=-11\)

P(x) + Q(x)= ( x^5 - 2x^2 + 7x^4 - 9x^3 - 1/4x) + ( 5x^4 - x^5 + 4x^2 - 2x^3 - 1/4)
= x^5 - 2x^2 + 7x^4 - 9x^3 - 1/4x + 5x^4 - x^5 + 4x^2 - 2x^3 - 1/4
= ( x^5 - x^5 ) - ( 2x^2 + 4x^2) + ( 7x^4 + 5x^4) - ( 9x^3 - 2x^3) - 1/4x - 1/4
= 6x^2 + 12x^4 - 6x^3 - 1/4x - 1/4
P(x) - Q(x)= ( x^5 - 2x^2 + 7x^4 - 9x^3 -1/4x) - ( 5x^4 - x^5 + 4x^2 - 2x^3 -1/4)
= x^5 - 2x^2 + 7x^4 - 9x^3 - 1/4x - 5x^4 + x^5 - 4x^2 + 2x^3 + 1/4
= ( x^5 + x^5) - ( 2x^2 - 4x^2) + ( 7x^4 - 5x^4) - ( 9x^3 + 2x^3) - 1/4x + 1/4
= 2x^5 - (-2)x^2 + 2x^4 - 11x^3 - 1/4x + 1/4
P(x)=x^5+ 7x^4- 9x^3+ 2x^2-1/4x-0
Q(x)=(-x^5+5x^4- 2x^3+ 4x^2+0x-1/4
= 12x^4-11x^3+ 6x^2-1/4x-1/4

18 - 4\(x\) = -20 - 6\(x\)
-4\(x\) + 6\(x\) = - 20 - 18
2\(x\) = - 38
\(x\) = - 19
h, -15 \(\times\) 24 = -7\(x\) + 32
7\(x\) = 360 + 32
7\(x\) = 392
\(x\) = 392:7
\(x\) = 56
i, 15\(x\) -3.(4\(x\) - 6) = -12 + 36
15\(x\) - 12\(x\) + 18 = 24
3\(x\) = 24 - 18
3\(x\) = 6
\(x\) = 2
k, -10\(x\) - 27 = -7\(x\) + 33
-27 - 33 = -7\(x\) + 10\(x\)
3\(x\) = -60
\(x\) = -20

P(x) = x^5 - 2x^2 + 7x^4 - 9x^3 - 1/4x
=x5+7x4-9x3-2x2-1/4x
Q(x) = 5x^4 - x^5 + 4x^2 - 2x^3 - 1/4
=-x5+5x4-2x3+4x2-1/4
P(x)+Q(x)=x5+7x4-9x3-2x2-1/4x -x5+5x4-2x3+4x2-1/4
=x5-x5+7x4+5x4-9x3-2x3-2x2+4x2-1/4x-1/4
=12x4-11x3+2x2-1/4x-1/4
P(x)-Q(x)=x5+7x4-9x3-2x2-1/4x +x5-5x4+2x3-4x2+1/4
=x5+x5+7x4-5x4-9x3+2x3-2x2-4x2-1/4x-1/4
=2x5+2x4-7x3-6x2-1/4x-1/4

Sửa đề : \(\frac{3}{4}x-\frac{1}{4}=2\left(x-3\right)-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=2x-6-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=\frac{7}{4}x+2x\)
\(-x-\frac{1}{4}=2x\)
\(-x-\frac{1}{4}-2x=0\)
\(-3x-\frac{1}{4}=0\)
\(-3x=\frac{1}{4}\Leftrightarrow x=-\frac{1}{12}\)

\(\Leftrightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Leftrightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Leftrightarrow\frac{-3}{2}x=\frac{-23}{4}\)
\(\Leftrightarrow x=\frac{23}{6}\)
\(4^{x+3}+4^{x}=1040\)
\(4^{x}.4^3+4^{x}=1040\)
\(4^{x}.\left(4^3+1\right)=1040\)
\(4^{x}.\left(64+1\right)=1040\)
\(4^{x}.65=1040\)
\(4^{x}=1040:65\)
\(4^{x}=16\)
\(4^{x}=4^2\)
\(x=2\)
\(Vậy\) \(x\) \(=\) \(2\)