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a) 207-10x+7=84
10x=130
x=13
b)=> 3x-15=0
3x=15
x=5
c) 53+132-x=184
132-x=131
x=1
d) 85-5x=25
5x=60
x=12
e) x-4=12
x=16
a/ 1260: [207-(10x-7)]=15
207-(10x-7) =1260:15= 84
10x-7= 207-84=123
10x=123+7=130
x= 130:10=13
b/1236.(3x-15)=0
3x-15= 0:1236=0
3x =0+15=15
x =15:3=5

(125 - 2x) . 6 = 126 - 12
(125 - 2x) . 6 = 114
(125 - 2x) = 114 : 6
(125 - 2x) = 19
2x = 125 - 19
2x = 106
x = 3
(54 : 52 - 4x) .2 - 13 = 44 : 42 + 5
(54 : 52 - 4x) .2 - 13 = 21
(54 : 52 - 4x) . 2 = 21 + 13
(54 : 52 - 4x) . 2 = 34
(54 : 52 - 4x) = 34 : 2
(54 : 52 - 4x) = 17
25 - 4x = 17
4x = 8
x = 2

a) \(6x-36=5^{12}:5^{10}-2012^0\)
\(6x-36=5^2-2012^0\)
\(6x-36=25-1\)
\(6x-36=24\)
\(6x\) \(=24+36\)
\(6x\) \(=60\)
\(x=60:6\)
\(x=10\)
Vậy \(x=10\)
b) \(2x-125=-65\)
\(2x\) \(=\left(-65\right)+125\)
\(2x\) \(=60\)
\(x=60:2\)
\(x=30\)
Vậy \(x=30\)
c) \(2012-120\left(4x+1\right)=932\)
\(120\left(4x+1\right)=2012-932\)
\(120\left(4x+1\right)=1080\)
\(4x+1=1080:120\)
\(4x+1=9\)
\(4x\) \(=9-1\)
\(4x\) \(=8\)
\(x=8:4\)
\(x=2\)
Vậy \(x=2\)
a) 6x - 36 = 512 : 510 - 20120
6x - 36 = 52 - 20120
6x - 36 = 25 - 1
6x - 36 = 24
6x = 24 + 36
6x = 60
x = 60 : 6
x = 10
Vậy x = 10
b) 2x - 125 = -65
2x = (-65) + 125
2x = 60
x = 60 : 2
x = 30
Vậy x = 30
c) 2012 - 120(4x + 1) = 932
120(4x + 1) = 2012 - 932
120(4x + 1) = 1080
4x + 1 = 1080 : 120
4x + 1 = 9
4x = 9 - 1
4x = 8
x = 8 : 4
x = 2
Vậy x = 2.
Chúc bạn học tốt!

1)=>3(x-5)(2x+9)+3(x-5)=0=>(x-5)(6x+30)
=>x-5=0=>x=5
6x+30=0=>x=-5
2)=>x^2-16=0=>x=+-4
12-4x=0=>x=3
3)=>9-x^2=0=>x=+-3
4x-8=0=>x=2
4)=>8-x^3=0=>x=3
5^x-125=0=>x=2
5)=>2^x.2^x=8=>2^2x=8=>2x=3=>x=1,5

a/ 38+59-148-38+59=(38-38) + (59+59) -148=118-148=-30
b/43-245+69-43-69=(43-43)-245+(69-69)=-245
c/ {1260+420-620}-1260-420-280=1260+420-620-1260-420-280=(1260-1260)+(420-420)-(620+280)=-900
tạm bài 1 vì fải đi ngủ rùi

a ) 126 - 2x = 12 - ( -28 )
126 - 2x = 40
2x = 126 - 40
2x = 86
x = 86 : 2
x = 43
b ) 25 - 5( x + 1 ) = 30 - 125
25 - ( 5x + 5 ) = -95
25 - 5x - 5 = -95
20 - 5x = -95
5x = 20 - ( - 95 )
5x = 115
x = 115 : 5
x = 23
c ) I 3x - 1 I - 25 = 73
I 3x - 1 I = 73 + 25
I 3x - 1 I = 98
=> 3x - 1 = 98 hoặc 3x - 1 = -98
=> 3x = 98 + 1 hoặc 3x = -98 + 1
=> 3x = 99 hoặc 3x = -97
=> x = 99 : 3 hoặc x = -97 : 3
=> x = 33 hoặc x = -93/3
d ) 2( x + 2 ) - 6 = 120 - 4x
2x + 4 - 6 = 120 - 4x
2x - 2 = 120 - 4x
2x + 4x = 120 + 2
6x = 122
x = 122 : 6
x = 61/3
[ ( 4x - 125 ) : 5 ] . 12 = 1260
[ ( 4x - 125 ) : 5 ] = 105
( 4x - 125 ) = 525
4x = 650
x = 162,5
\(\left[\left(4x-125\right):5\right].12=1260\)
\(\Leftrightarrow\left(4x-125\right):5=105\)
\(\Leftrightarrow4x-125=525\)
\(\Leftrightarrow4x=650\)
\(\Leftrightarrow x=\frac{650}{4}=162,5\)