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a,5 mũ 15
b,3 mũ 0=1
c,11 mũ 3
d,10 mũ 2
e,17 mũ 0=1
g,25 mũ 17
f,16 mũ 3
Chúc bạn học tốt,nhớ k cho mình nha
a) \(9.x-2.x=\frac{6^{27}}{6^{25}}+\frac{48}{12}\)
\(\Leftrightarrow7x=6^2+4\)
\(\Leftrightarrow7x=36+4=40\)
\(\Leftrightarrow x=\frac{40}{7}\)
Vậy : \(x=\frac{40}{7}\)
b) \(11^x=5.x+\frac{5^{31}}{5^{29}}+3.2^2-10^0\)
\(\Leftrightarrow11^x=5x+5^2+12-1\)
\(\Leftrightarrow11^x=5x+36\)
\(\Rightarrow x\in\varnothing\)
a) \(27^7\div9^{10}\)
\(=\left(3^3\right)^7\div\left(3^2\right)^{10}\)
\(=3^{3\times7}\div3^{2\times10}\)
\(=3^{21}\div3^{20}\)
\(=3^1\)
\(=3\)
b) \(125^6\div25^7\)
\(=\left(5^3\right)^6\div\left(5^2\right)^7\)
\(=5^{3\times6}\div5^{2\times7}\)
\(=5^{18}\div5^{14}\)
\(=5^4\)
\(=625\)
c) \(5^{15}\div5^3\)
\(=5^{12}\)
\(=244140625\)
d) \(11^7\div11^3\)
\(=11^4\)
\(=14641\)
e) \(125\div5^2\)
\(=5^2\div5^2\)
\(=5^1\)
\(=5\)
g) \(169\div13^2\)
\(=13^2\div13^2\)
\(=13^1\)
\(=13\)
1) \(2^x-15=17\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
2) \(\left(7x-11\right)^3=25\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=825\)
\(\Leftrightarrow7x-11=\sqrt[3]{825}\)
\(\Leftrightarrow7x=11+\sqrt[3]{825}\)
\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)
3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)
\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
4) \(4x+5\left(x+3\right)=105\)
\(\Leftrightarrow9x+15=105\)
\(\Leftrightarrow9x=90\)
\(\Rightarrow x=10\)
5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)
\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)
\(\Leftrightarrow3x+4=34\)
\(\Leftrightarrow3x=30\)
\(\Rightarrow x=10\)
1) 62 . x = 36
=> x = 36 / 36 = 1
2) 9x - 42 = 11
9x - 16 = 11
9x = 11 + 16 =27
=> x = 27/9=3
3) 10 + 2x = 42
2x = 16 - 10 =6
=> x = 3
4) 231 - ( x - 6 ) =103
( x - 6 ) = 231-103=128
=> x = 128+6=134
5) 10 + 3x = 45 / 42
3x = 43-10=64-10=54
x = 18
6)25 + 52x = 82 + 62
25 + 25x = 100
25x = 100-25=75
=> x = 75/25=3
*Chúc bạn học tốt*
1) 62.x=36 2) 9.x-42=11 3)10+2.x=42 4)231-(x-6)=103 5)10+3x=45:42 6)25+52.x=82+62
36.x=36 9.x-16=11 10+2.x=16 x-6 = 231-103 10+3x=43 25+25.x =64+36
x=36:36 9.x =11+16 2.x =16-10 x-6 =128 10+3x=64 25+25.x =100
x=1 9.x =27 2.x =6 x =128+6 3x=64-10 25.x =100-25
x =27:9 x =6:2 x =134 3x=54 25.x =75
x =3 x =3 x=54:3 x =75:25
x=18 x =3
\(3^6\) và \(8^2\)
\(8^2=\left(2^3\right)^2=2^6\)
\(\Rightarrow3^6>8^2\)
a) \(5^3\) và \(3^5\)
Vì : \(5^3=125\)
\(3^5=243\)
Vì 125 < 243 ⇔ \(5^3< 3^5\)
b) \(3^6\) và \(8^2\)
⇒ \(3^6=3^{3.2}=\left(3^3\right)^2=9^2\)
Vì \(9^2>8^2\) ⇔ \(3^6>8^2\)
c) \(16^{19}\) và \(8^{25}\)
⇒ \(16^{19}=\left(2^4\right)^{19}=2^{4.19}=2^{76}\)
⇒ \(8^{25}=\left(2^3\right)^{25}=2^{3.25}=2^{75}\)
Vì \(2^{76}>2^{75}\) ⇔ \(16^{19}>8^{25}\)
d) \(2^{12}\) và \(3^8\)
⇒ \(2^{12}=2^{3.4}=\left(2^3\right)^4=8^4\)
⇒ \(3^8=3^{2.4}=\left(3^2\right)^4=9^4\)
Vì \(8^4< 9^4\) ⇔ \(2^{12}< 3^8\)
e) \(27^{11}\) và \(81^8\)
⇒ \(27^{11}=\left(3^3\right)^{11}=3^{3.11}=3^{33}\)
⇒ \(81^8=\left(3^4\right)^8=3^{4.8}=3^{32}\)
Vì \(3^{33}>3^{32}\) ⇔ \(27^{11}>81^8\)
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