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\(\frac{7}{9}+\frac{16}{48}< x< \frac{43}{8}+0.125\)
\(\frac{10}{9}< x< \frac{11}{2}\)
\(1.11< x< 5.5\)
Vậy \(x=2;3;4;5.\)
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Giải:
a) \(\left(4,5-2x\right).\left(-1\dfrac{4}{7}\right)=\dfrac{11}{14}\)
\(\Leftrightarrow\left(4,5-2x\right).\left(-\dfrac{3}{7}\right)=\dfrac{11}{14}\)
\(\Leftrightarrow4,5-2x=\dfrac{11}{14}:\left(-\dfrac{3}{7}\right)=-\dfrac{11}{6}\)
\(\Leftrightarrow2x=4,5-\left(-\dfrac{11}{6}\right)\)
\(\Leftrightarrow2x=\dfrac{19}{3}\)
\(\Leftrightarrow x=\dfrac{19}{3}:2=\dfrac{19}{6}\)
Vậy ...
b) \(\dfrac{4}{9}x=\dfrac{9}{8}-0,125\)
\(\Leftrightarrow\dfrac{4}{9}x=\dfrac{9}{8}-\dfrac{1}{8}\)
\(\Leftrightarrow\dfrac{4}{9}x=1\)
\(\Leftrightarrow x=1:\dfrac{4}{9}=\dfrac{9}{4}\)
Vậy ...
Các câu còn lại làm tương tự.
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\(x=\left[6\frac{3}{5}:6-0,125\cdot8+2\frac{2}{15}\cdot0,05\right]\cdot\frac{11}{4}\)
\(\Leftrightarrow x=\left[\frac{33}{5}:6-\frac{1}{8}\cdot8+\frac{32}{15}\cdot\frac{1}{20}\right]\cdot\frac{11}{4}\)
\(\Leftrightarrow x=\left[\frac{33}{5}\cdot\frac{1}{6}-\frac{1}{8}\cdot8+\frac{32}{15}\cdot\frac{1}{20}\right]\cdot\frac{11}{4}\)
\(\Leftrightarrow x=\left[\frac{11}{5}\cdot\frac{1}{2}-1+\frac{8}{15}\cdot\frac{1}{5}\right]\cdot\frac{11}{4}\)
\(\Leftrightarrow x=\left[\frac{11}{10}-1+\frac{8}{75}\right]\cdot\frac{11}{4}\)
\(\Leftrightarrow x=\left[\frac{1}{10}+\frac{8}{75}\right]\cdot\frac{11}{4}\)
Tính nốt đi nhé Nguyển Lương Hiếu
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mik làm được mỗi ý b thui :
b ) \(\frac{169}{10}=16,9\)
mik nha
phần đầu bằng -6675/128
phần sau bằng 13
bạn dùng máy tính là được mà
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mình đang cần gấp câu trả lời ,bạn nào giải được nhanh k luôn ,hứa đấy
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\(y.0.25=3.6+\frac{7}{20}\)
\(y.0.25=\frac{79}{20}=3.95\)
\(y=3.95:0.25=\frac{79}{5}=15.8\)
y x 0,125 = 3,6 + 2.8 : 8
y x 0,125 = 3,6 + 0,35
y x 0,125 = 3,95
y = 3,95 : 0,125
y = 31,6
k mik nha
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Câu 13 :
\(\left(-\frac{1}{4}+\frac{5}{8}\right)+-\frac{3}{5}\)
\(=\frac{3}{8}-\frac{-3}{5}\)
\(=\frac{39}{40}\)
Câu 14 :
\(M=\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1=\frac{5}{9}\)
Câu 15 :
\(E=\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=\left(-\frac{3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=0\)
Câu 16 :
\(H=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}\right)+\frac{7}{8}:\left(\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}+\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\frac{-7}{24}=-3\)
huhuhuhuhuhuhuhuhuhuhuhuhu giúp mk đi
Plssssssssssssssssssssssssssssssssssssssssssssss
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1) |x + 2| = 4
\(\Leftrightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=-6\end{cases}}\)
2) 3 – |2x + 1| = (-5)
\(\Leftrightarrow\left|2x+1\right|=8\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}\)
3) 12 + |3 – x| = 9
\(\Leftrightarrow\left|3-x\right|=-3\)(vô lí)
=>\(x=\varnothing\)
1) I x+2 I=4
\(\Rightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-6\end{cases}}}\)
2) \(3-|2x+1|=-5\)
\(\Leftrightarrow|2x+1|=8\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-9\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}}\)
3) \(12+|3-x|=9\)
\(\Leftrightarrow|3-x|=-3\)(vô lí vì I 3-x I \(\ge\)0)