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\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
37 : x . 46 : 37 + 23 = 69
37 : x . 46/37 = 69 - 23
37 : x . 46/37 = 46
37 : x = 46 : 46/37
37 : x = 37
x = 37 : 37
x = 1
1/3 x 46 +2/3x37 3,2x (95x10) +(8x4)x 187 -(32x 10) x 8,2
=(1/3+2/3) x (46+37) 32x95+32x 187- 32x 82
= 1x 100 32x( 95+187-82)
= 100 = 32 x200
= 6400
Chuyển dấu " - " ở 23 qua cho 37
= -37 . ( 17 + 23 - 46 )
= -37 . ( -6)
= 222
\(17.\left(-37\right)-23.37-46.\left(-37\right)\)
\(=\left(-37\right).\left(17+23-46\right)\)
\(=\left(-37\right).\left(-6\right)\)
\(=222\)
17*(-37)-23*37-46*(-37)
=17*(-37)+23(-37)-46(-37)
=(-37)(17+23-46)=(-37)(-6)=222
a) -37 + 54 + (-70) + (-163) +246
= (-37-163) + (54+246) - 70
= -200 + 300 -70
= 30
chuc bn hoc tot
(x+y+z)+(x+z+t)+(y+z+t)+(x+y+t)=46+41+44+37=168
=>3x+3y+3z+3t=168
=>3(x+y+z+t)=168
=>x+y+z+t=56
Thay x+y+z+t=168 vào rồi tính ta được
x=x+y+z+t-(y+z+t)=56-44=12
y=x+y+z+t-(x+z+t)=56-41=15
z=x+y+z+t-(x+y+t)=56-37=19
t=x+y+z+t-(x+y+z)=56-46=10