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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
30 tháng 6 2024
a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{55}{24}\)
NT
2
15 tháng 7 2015
5/3+8/5(1/3+4/7).4/5
=5/3+8/5.(7/21+12/21).4/5
=5/3+8/5.19/21.4/5
=5/3+608/525
=857/525+608/525
=1483/525
15 tháng 7 2015
sửa 5/3+(1/3.8/5+8/5.4/7).4/5 nha xin lỗi mình cần rất gấp
AF
21 tháng 9 2020
Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
26 tháng 4 2021
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)
9 tháng 8 2018
\(6x\frac{7}{8}+\frac{9}{10}:\frac{5}{3}\)
=\(\frac{42}{8}+\frac{9}{10}x\frac{3}{5}\)
=\(\frac{21}{4}+\frac{21}{50}\)
=\(\frac{525}{100}+\frac{42}{100}\)
=\(\frac{567}{100}\)
=\(\frac{4}{5}:2x\frac{8}{9}:4\)
=\(\frac{4}{5}x\frac{1}{2}x\frac{8}{9}x\frac{1}{4}\)
=\(\frac{4x1x2x4x1}{5x2x9x4}\)
=\(\frac{4}{45}\)
23 tháng 6 2016
\(\frac{4}{3}:\frac{5}{4}:\frac{6}{5}:\frac{7}{6}:\frac{8}{7}:\frac{9}{8}\)
=\(\frac{4}{3}\times\frac{4}{5}\times\frac{5}{6}\times\frac{6}{7}\times\frac{7}{8}\times\frac{8}{9}\)
=\(\frac{16}{27}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 8 2023
c)\(\dfrac{3}{8}\times\dfrac{5}{8}+y=\dfrac{5}{4}\)
\(\dfrac{15}{64}+y=\dfrac{5}{4}\)
\(y=\dfrac{5}{4}-\dfrac{15}{64}\)
\(y=\dfrac{65}{64}\)
d, \(\dfrac{3}{8}+\dfrac{5}{8}\times y=\dfrac{5}{4}\)
\(\dfrac{5}{8}\times y=\dfrac{5}{4}-\dfrac{3}{8}\)
\(\dfrac{5}{8}\times y=\dfrac{7}{8}\)
\(y=\dfrac{7}{8}:\dfrac{5}{8}\)
\(y=\dfrac{7}{5}\)
21 tháng 8 2023
a, 3/4 x y = 3/5 + 3/10
3/4 x y = 9/10
y = 9/10 : 3/4
y = 6/5
b, 3/5 : y = 3/4 - 2/5
3/5 : y = 7/20
y = 3/5 : 7/20
y = 12/7
PT
15 tháng 9 2018
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+1028=(1+2+3+4+5+6+7+8+9)x3+1028=45x3+1028=135+1028=1163
TV
2
1 tháng 10 2017
\(\frac{5}{6}+\frac{7}{9}:\frac{5}{6}-\frac{1}{6}\)
\(=\left(\frac{5}{6}-\frac{1}{6}\right)+\frac{7}{9}.\frac{6}{5}\)
\(=\frac{2}{3}+\frac{14}{15}\)
\(=\frac{10}{15}+\frac{14}{15}=\frac{24}{15}\)
\(\frac{8}{11}.\frac{7}{8}+\frac{8}{11}:\frac{4}{5}\)
\(=\frac{7}{11}+\frac{8}{11}.\frac{5}{4}\)
\(=\frac{7}{11}+\frac{10}{11}\)
\(=\frac{17}{11}\)
M
1 tháng 10 2017
\(\frac{5}{6}+\frac{7}{9}:\frac{5}{6}-\frac{1}{6}\) \(\frac{8}{11}x\frac{7}{8}+\frac{8}{11}:\frac{4}{5}\)
\(=\frac{5}{6}+\frac{14}{15}-\frac{1}{6}\) \(=\frac{8}{11}x\frac{7}{8}+\frac{8}{11}x\frac{5}{4}\)
\(=\left(\frac{5}{6}-\frac{1}{6}\right)+\frac{14}{15}\) \(=\frac{8}{11}x\left(\frac{7}{8}+\frac{5}{4}\right)\)
\(=\frac{2}{3}+\frac{14}{15}\) \(=\frac{8}{11}x\frac{17}{8}\)
\(=\frac{8}{5}\) \(=\frac{17}{11}\)