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a) S=1+52+54+.....+5200
=>52S=25S=52+54+56+.....+5202
=>25S-S=(52+54+56+....+5202)-(1+52+54+......+5200)
=>24S=5202-1
=>S=\(\frac{5^{202}-1}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có 3^21>3^20
suy ra:3^20=(3^2)^10=9^10
2^31>2^30
suy ra:(2^3)^10=8^10
vì 8<9.Suy ra 2^31<3^21
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ta có 45.32+210-23.30
= (22)5.32+210-23.30
= 23.27.32+23.27-23.30
= 23(27.32+27-30)
= 23[27(9+1)-3.10]
= 23[27.10-3.10]
= 23(27-3).10
= 10000
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Ta có: \(4^{30}=2^{30}.2^{30}=\left(2^3\right)^{10}.\left(2^2\right)^{15}=8^{10}.4^{15}>8^{10}.3^{15}>8^{10}.3^{11}\) (1)
Mà \(8^{10}.3^{11}=8^{10}.3^{10}.3=\left(8.3\right)^{10}.3=24^{10}.3\) (2)
Từ (1);(2)=> \(4^{30}>3.24^{10}\)
Vậy \(2^{30}+3^{30}+4^{30}>3.24^{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^{20}+3^{30}+4^{30}=4^{10}+9^{10}+64^{10}<64^{10}+64^{10}+64^{10}=3.64^{10}\)
\(324^{10}>320^{10}=\left(5.64\right)^{10}=5^{10}.64^{10}>3.64^{10}\)
\(\Rightarrow2^{20}+3^{30}+4^{30}<324^{10}\)
=10000
học tốt
=1024.9+1024-8.30
=1024.(9-8).30
=1024.30
=30720