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Bài 3 :
a) 4.(x-5) - 2 3=24.3
4x-20-8=48
4x=76
x=19
b) 4.x3+15=271
4.x3=256
x3=64
=> x=4
c) ( 2x-3)2= 169
=> 2x-3= 13
2x=16
x=8
Chúc bạn học tốt !
4*(x-5) - 2^3 = 2^4*3
4*(x-5) - 8 = 16*3
4*(x-5) - 8 = 48
4*(x-5) = 48 + 8
4*(x-5) = 56
x- 5 = 56 : 4
x - 5 = 14
x = 14 + 5
x = 19
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Bài 1:
a) \(4^{x+2}+4^x=68\)
\(\Rightarrow4^x\cdot\left(4^2+1\right)=68\)
\(\Rightarrow4^x\cdot17=68\)
\(\Rightarrow4^x=\dfrac{68}{17}\)
\(\Rightarrow4^x=4\)
\(\Rightarrow4^x=4^1\)
\(\Rightarrow x=1\)
b) \(5\cdot2^{x+4}-3\cdot2^x=308\)
\(\Rightarrow2^x\cdot\left(5\cdot2^4-3\right)=308\)
\(\Rightarrow2^x\cdot\left(5\cdot16-3\right)=308\)
\(\Rightarrow2^x\cdot77=308\)
\(\Rightarrow2^x=\dfrac{308}{77}\)
\(\Rightarrow2^x=4\)
\(\Rightarrow2^x=2^2\)
\(\Rightarrow x=2\)
c) \(4\cdot3^{x+1}+7\cdot3^x=513\)
\(\Rightarrow3^x\cdot\left(4\cdot3+7\right)=513\)
\(\Rightarrow3^x\cdot19=513\)
\(\Rightarrow3^x=\dfrac{513}{19}\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
d) \(5^{x+4}-5^x=3120\)
\(\Rightarrow5^x\cdot\left(5^4-1\right)=3120\)
\(\Rightarrow5^x\cdot\left(625-1\right)=3120\)
\(\Rightarrow5^x\cdot624=3120\)
\(\Rightarrow5^x\cdot\dfrac{3120}{624}\)
\(\Rightarrow5^x=5\)
\(\Rightarrow5^x=5^1\)
\(\Rightarrow x=1\)
f) \(3\cdot4^{2x+1}-16^x=2816\)
\(\Rightarrow3\cdot4^{2x+1}-\left(4^2\right)^x=2816\)
\(\Rightarrow3\cdot4^{2x+1}-4^{2x}=2816\)
\(\Rightarrow4^{2x}\cdot\left(3\cdot4-1\right)=2816\)
\(\Rightarrow4^{2x}\cdot11=2816\)
\(\Rightarrow4^{2x}=\dfrac{2816}{11}\)
\(\Rightarrow4^{2x}=256\)
\(\Rightarrow\left(2^2\right)^{2x}=2^8\)
\(\Rightarrow2^{4x}=2^8\)
\(\Rightarrow4x=8\)
\(\Rightarrow x=2\)
Bài 2:
\(2^x+124=5^y\)
\(\Rightarrow5^y-2^x=124\)
\(\Rightarrow5^y-2^x=125-1\)
\(\Rightarrow\left\{{}\begin{matrix}5^y=125\\2^x=1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}5^y=5^3\\2^x=2^0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}y=3\\x=0\end{matrix}\right.\)
Vậy: ....
Tìm x
(5x —2).7=49
Và bài tính bằng cách thuận tiện:
2. 3^2+4.3^3
^ là mũ 2.3^=mũ 2
Các bn giúp mình với
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Bài 1 :
( 5x - 2 ) . 7 = 49
5x - 2 = 49 : 7
5x - 2 = 7
5x = 7 + 2
5x =9
x = 9: 5
x = \(\frac{9}{5}\)
Vậy x = \(\frac{9}{5}\).
Bài 2 :
\(2.3^2+4.3^3=2.3^2+2.2.3^2.3=2.3^2.\left(1+2.3\right)\)
\(=18.7\)
\(=126\)
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119 - (25 - x4)2 = 38
=> (25 - x4)2 = 119 - 38 = 81
=> (25 - x4)2 = (\(\pm\)9)2
=> \(\orbr{\begin{cases}25-x^4=9\\25-x^4=-9\end{cases}}\Rightarrow\orbr{\begin{cases}x^4=16\\x^4=34\end{cases}}\Rightarrow x=\pm2\)
\(119-\left(25-x^4\right)^2=38\)
\(\Leftrightarrow\left(25-x^4\right)^2=119-38=81\) \(=\left(\pm9\right)^2\)
TH1: nếu \(25-x^4=9\) thì ta được: \(x^4=25-9=16=\left(\pm4\right)^2\)
TH2: nếu \(25-x^4=-9\) thì ta được: \(x^4=25+9=34=\left(\pm\sqrt{34}\right)^2\)
Vậy \(x\in\left\{-\sqrt{34};-4;4;\sqrt{34}\right\}\)