Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(42-2\left(32-2^{x+1}\right)=10\)
\(\Leftrightarrow2\left(32-2^{x+1}\right)=42-10=32\)
\(\Leftrightarrow32-2^{x+1}=16\)
\(\Leftrightarrow2^{x+1}=32-16=16\)
\(\Leftrightarrow2^{x+1}=2^4\)
\(\Leftrightarrow x+1=4\)
\(\Rightarrow x=3\)
\(42-2\left(32-2^{x+1}\right)=10\)
\(\Leftrightarrow2^{x+1}=16\)
\(\Leftrightarrow2^{x+1}=2^4\)
=> x = 4
\(42-2.\left(32-2^{x+1}\right)=10\)
\(2.\left(32-2^{x+1}\right)=42-10\)
\(2.\left(32-2^{x+1}\right)=32\)
\(32-2^{x+1}=32:2\)
\(32-2^{x+1}=16\)
\(2^{x+1}=32-16\)
\(2^{x+1}=16\)
\(2^{x+1}=2^4\)
\(x+1=4\)
\(x=4-1\)
\(x=3\)
\(42-2\left(3x-2^{x+1}\right)=10\)
\(2\left(32-2^{x+1}\right)=32\)
\(32-2^{x+1}=16\)
\(2^{x+1}=16\)
\(2^{x+1}=2^4\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=3\)
Vậy x = 3
a, 3x - 5 = 16...............
=> 3x = 16 + 5 = 21..................
=> x = 21 : 3 = 7..........
\(b,42-2\left(32-2^{x+1}\right)=10\)
\(\Rightarrow2\left(32-2^{x+1}\right)=42-10=32\)
\(\Rightarrow32-2^{x+1}=32:2=16\)
\(\Rightarrow2^{x+1}=32-16=16=2^4\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=4-1=3\)
\(32-2\left(x+1\right)=42\)
\(\Rightarrow32-2x-1=42\)
\(\Rightarrow31-2x=42\)
\(\Rightarrow2x=31-42\)
\(\Rightarrow2x=-11\)
\(\Rightarrow x=\frac{-11}{2}\)
\(\Rightarrow x=-5,5\)
36.72-36.67=36.(72-67)=36.5=180 {296:[78-(579-30.7):9]}.18={296:[78-369:9]}.18=296:37.18=8.18=144 3x-5=16=3x-5=16+5.3x+5=21.x = 21:3.x = 7 vay x =7 phan kia minh ko bie,bn thong cam cho minh nha.minh can nhgieng cuu
\(36\cdot72-36\cdot67\)
\(=36\left(72-67\right)\)
\(=36\cdot5\)
\(=180\)
42 - 2.(32 - 2x + 1) = 10
2.(32 - 2x + 1) = 42 - 10 = 32
32 - 2x + 1 = 32 : 2 = 16
32 - 2x = 16 - 1 = 15
2x = 32 - 15 = 17
Hình như đề bài sai hay sao í bạn
\(\Leftrightarrow-2\left(32+1-2^x\right)=10-42=-32\\ \Leftrightarrow2\left(33-2^x\right)=32 \\ \Leftrightarrow33-2^x=16\\ \Leftrightarrow-2^x=-17\\ \Leftrightarrow2^x=17\)
mình thấy đề sai sai
bạn ktra lại nhé