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a) \(5^{36}\)= \(\left(5^3\right)^{12}\)= \(125^{12}\)
\(11^{24}\)= \(\left(11^2\right)^{12}\)= \(121^{12}\)
Vì \(125^{12}\)> \(121^{12}\)
Nên ..........................
b) tương tự :)

A= (2+22)+(23+24)+...+(259+260)
A=2.(1+2)+23.(1+2)+...+259.(1+2)
A=2.3+23.3+...+259.3
A=3.(2+23+...+259)
Vì 3 chia hết cho 3 => 3.(2+23+...+259) chia hết cho 3
=>A chia hết cho 3
A= (2+22+23)+...+(258+259+260)
A=2.(1+2+22)+...+258.(1+2+22)
A=2.7+...+258.7
A=7.(2+...+258)
Vì 7 chia hết cho 7 =>7.(2+...+258) chia hết cho 7
=>A chia hết cho 7
A= (2+22+23+24)+...+(257+258+259+260)
A=2.(1+2+22+23)+...+257.(1+2+22+23)
A=2.15 +...+257.15
A=15.(2+...+257)
vì 15 chia hết cho 15 =>15.(2+...+25) chia hết cho 15
=>A chia hết cho 15

A=2+22+23+...+230
2A= 22+23+...+230+231
2A-A=231-1
A=231-1
a) A=230.2-1 \(⋮\)2


\(a,10^{30}=\left(10^3\right)^{10}=1000^{10}\)
\(2^{100}=\left(2^{10}\right)^{10}=1024^{10}\)
\(1000^{10}< 1024^{10}\Rightarrow10^{30}< 2^{100}\)
\(b,2^{91}=\left(2^{13}\right)^7=8192^7\)
\(5^{35}=\left(5^5\right)^7=3124^7\)
\(8192^7>3124^7\)
\(\Rightarrow2^{91}>5^{35}\)
\(c,2^{1000}=\left(2^{10}\right)^{100}=1024^{100}\)
\(5^{400}=\left(5^4\right)^{100}=625^{100}\)
\(1024^{100}>625^{100}\)
\(\Rightarrow2^{1000}>5^{400}\)

\(a,5^2.36+25.4\)
\(=25.36+25.4\)
\(=25.\left(36+4\right)\)
\(=25.40\)
\(=1000\)
\(b,7^9.7^7:7^{15}-7^0\)
\(=7^{16}:7^{15}-1\)
\(=7-1\)
\(=6\)
a) 52.36 + 25 .4
= 25.36 + 25 .4
=25 . ( 36 + 4 )
=25 . 40
=25.4.10
=100.10
=1000

\(x^6:x^3=125\)
\(x^3=125\)
\(x^3=5^3\)
\(\Rightarrow x=5\)
b, \(3.2^x-3=45\)
\(3.2^x=45+3\)
\(3.2^x=48\)
\(2^x=48:3\)
\(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
c, \(1500:\left[\left(30+40\right):x\right]=30\)
\(1500:\left[70:x\right]=30\)
\(70:x=1500:30\)
\(70:x=50\)
\(x=70:50\)
\(x=\frac{70}{50}\)
\(x=\frac{7}{5}\)
d, \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:40\)
\(41-\left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28:2\)
\(x=14\)
bạn thử lại nhé
Ta có x20=x1
=> x=0 hoặc x=1
x6:x3=x6-3=x3=125
=>x3=53
=> x=5
Ta có
4x3+12=120
=>4x3=108
=>x3=27
=>x=3
Ta có
3.2x-3=45
=>3(2x-1)=45
=>2x-1=15
=>2x=16
=> x=2 hoặc x=-2
Ta có 1500:[(30+40):x]=30
=>70:x=50
=> x=7/5
Ta có
720:[41-(2x-5)]=23.5
=>41-(2x-5)=720:40=18
=> 2x-5=23
=>x=(23+5):2=14
KL