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\(-\left(+51\right);-|-39|;-37;0;|-18|;-\left(-19\right);25\)
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\(a,\frac{\left(21\right)^{15}.49^{11}.5^6}{\left(63\right)^{14}.7}=\frac{\left(3.7\right)^{15}.\left(7^2\right)^{11}.5^6}{\left(3^2.7\right)^{14}.7}=\frac{3^{15}.7^{15}.7^{22}.5^6}{\left(3^2\right)^{14}.7^{14}}=\frac{3^{15}.7^{37}.5^6}{3^{28}.7^{14}}\)
\(=\frac{7^{23}.5^6}{3^{13}}\)
sao số to thế nhỉ
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sao ban ghi duoc dau gach gang duoi phan so vay chi cho minh nha
Cau a va b dat thua so chung
Cau c phan h thanh tong cua 1 va 1 phan so
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Ta có :
\(14^4.4^2.21^5.28^3.18^3\)
\(=\left(7.2\right)^{14}.\left(2^2\right)^2.\left(7.3\right)^5.\left(7.2^2\right)^3.\left(3^2.2\right)^3\)
\(=7^{14}.2^{14}.2^4.7^5.3^5.7^3.2^6.3^6.2^3\)
\(=\left(7^{14}.7^5.7^3\right)\left(2^{14}.2^4.2^6.2^3\right)\left(3^5.3^6\right)\)
\(=7^{22}.2^{27}.3^{11}\)
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\(A=\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)
\(B=\frac{9^{14}.25^7.8^7}{18^{12}.625^3.24^3}=\frac{\left(3^2\right)^{14}.\left(5^2\right)^7.\left(2^3\right)^7}{\left(2.3^2\right)^{12}.\left(5^4\right)^3.\left(2^3.3\right)^3}=\frac{3^{28}.5^{14}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}=\frac{3^{28}.5^{14}.2^{21}}{2^{21}.3^{27}.5^{12}}=3.5^2=3.25=75\)
\(C=\frac{1+3+5+...+19}{21+23+25+...+39}=\frac{\left(19+1\right).10:2}{\left(39+21\right).10:2}=\frac{100}{300}=\frac{1}{3}\)
\(D=\frac{71.52+53}{530.71-180}=\frac{3745}{37450}=\frac{1}{10}\).
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1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
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2017^0-5*x=-49 =>1-5*x=-49 => 5*x = 49 + 1 => 5*x=50 => x=10
-17*53-21*(-17)-17 =(-17)*(53-21+1)=(-17)*23=391