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a, 3x+2 +3x = 90
3x . 32 + 3x = 90
3x. ( 32 + 1 ) = 90
3x . 10 =90
3x = 90 : 10
3x = 9
3x = 32
x = 2
1+2+3+......+x =210
(x+1) . x : 2= 210
(x+1) . x = 210 .2
(x+1) .x = 420
21 . 20 = 420
x = 20
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\(3^{x+2}+3^x=90\)
\(3^x\left(3^2+1\right)=90\)
\(3^x\left(9+1\right)=90\)
\(3^x\times10=90\)
\(3^x=\frac{90}{10}\)
\(3^x=9\)
\(3^x=3^2\)
x = 2
3x+2+3x=90
3x.32+3x=90
3x(32+1)=90
3x.10=90
3x=9
3x=32
=> x=2
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\(3^{x+2}+3^x=90\)
\(\Rightarrow3^x.3^2+3^x=90\)
\(\Rightarrow3^x\left(3^2+1\right)=90\)
\(\Rightarrow3^x.10=90\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
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\(3^{x-2}+3^x=90\)
\(3^{x-2}.1+3^{x-2}.3^2=90\)
\(3^{x-2}.\left(1+3^2\right)=90\)
\(3^{x-2}.10=90\)
\(3^{x-2}=90:10\)
\(3^{x-2}=9\)
\(3^{x-2}=3^2\)
\(x-2=2\)
\(x=4\)
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\(3^x+3^x+2=90\)
\(\Leftrightarrow3^x\left(1+1\right)+2=90\)
\(\Leftrightarrow3^x.2+2=90\)
\(\Leftrightarrow3^x.2=92\)
\(\Leftrightarrow3^x=46\)
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a: \(\dfrac{x}{x+3}=\dfrac{2}{5}\)
=>5x=2x+6
=>3x=6
hay x=2
b: \(\left(x+\dfrac{1}{2}\right)^2-\dfrac{1}{3}=\dfrac{1}{9}\)
\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{4}{9}\)
=>x+1/2=2/3 hoặc x+1/2=-2/3
=>x=1/6 hoặc x=-7/6
c: \(\left(x-\dfrac{1}{2}\right)^3+\dfrac{1}{4}=\dfrac{3}{8}\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)^3=\dfrac{3}{8}-\dfrac{2}{8}=\dfrac{1}{8}\)
=>x-1/2=1/2
hay x=1
d: \(2^{x+3}=32\)
=>x+3=5
hay x=2
e: \(\Leftrightarrow3^x\left(3^2+1\right)=90\)
\(\Leftrightarrow3^x=9\)
hay x=2
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3x-2 + 3x = 90
=> 3x : 32 + 3x = 90
=> 3x . 1/9 + 3x = 90
=> 3x.(1/9 + 1) = 90
=> 3x = 90 : 10/9
=> 3x = 81
=> 3x = 34
=> x = 4
Vậy x = 4
Vì 90=3^2+3^4
=> 3^(x-2)=3^2=> x=4
Và 3^x=3^4=> x=4
Vậy : x=4
3x + 3x + 2 = 90
3x + 3x x 32 = 90
3x x ( 1 + 9 ) = 90
3x x 10 = 90
3x = 90 : 10 = 9
=> 3x = 32 = > x = 2
Vậy x = 2
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