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a/ => x3 = 64 => x3 = 43 => x = 4
b/ => x5 = 32 => x5 = 25 => x = 2
c/ => 3x = 81 => 3x = 34 => x = 4
d/ => 3x+2 = 243 => 3x+2 = 35 => x + 2 = 5 => x = 3
e/ => (x - 2)3 = 64 => (x - 2)3 = 43 => x - 2 = 4 => x = 6
f/ => (x - 8)2 = 81 => (x - 8)2 = 92 => x - 8 = 9 => x = 17
12-(2-x)2=3
(2-x)2=12-3
(2-x)2=9
(2-x)2=32
2-x=3
x=2-3
x=-1
a) \(\frac{18^4.3^2.8^3}{27^3.16^2}=\frac{\left(2.3^2\right)^4.3^2.\left(2^3\right)^3}{\left(3^3\right)^3.\left(2^4\right)^2}=\frac{2^4.2^9.3^8.3^2}{3^9.2^8}=\frac{2^{13}.3^{10}}{3^9.2^8}=3.2^5=96\)
b) \(\frac{35^5.9^3.8^5}{81^4.32^5}=\frac{35^5.\left(3^2\right)^3.\left(2^3\right)^5}{\left(3^4\right)^4.\left(2^5\right)^5}=\frac{35^5.3^6.2^{15}}{3^{16}.2^{25}}=\frac{35^5}{3^{10}.2^{10}}=\frac{35^5}{6^{10}}\)
c) \(\frac{48^5.18^2}{81^2.34^4}=\frac{\left(2^4.3\right)^5.\left(2.3^2\right)^2}{\left(3^4\right)^2.\left(2.17\right)^4}=\frac{2^{20}.3^5.2^2.3^4}{3^8.2^4.17^4}=\frac{2^{22}.3^9}{3^8.2^4.17^4}=\frac{2^{18}.3}{17^4}\)
d) \(\frac{54^7.27^3.16^2}{243^2.64^3}=\frac{\left(2.3^3\right)^7.\left(3^3\right)^3.\left(2^4\right)^2}{\left(3^5\right)^2.\left(2^6\right)^3}=\frac{2^7.3^{21}.3^9.2^8}{3^{10}.2^{18}}=\frac{2^{15}.3^{30}}{3^{10}.2^{18}}=\frac{3^{20}}{2^3}\)
3\(^x\) . 3 = 43
=> 3\(^{\left(x+1\right)}\) = 43
=> Không có giá trị x thoả mãn .
49 . \(7^x\) = 2041
7\(^2\) . 7\(^x\) = 2041
7\(^{\left(x+2\right)}\) = 2041
=> \(7^{\left(x+2\right)}\) = 7\(^4\)
=> x + 2 = 4
=> x = 2
\(3^x+3^{x+2}=9^{17}+27^{12}=3^{34}+3^{36}\Rightarrow3^x=3^{34}\Leftrightarrow x=34\)
\(\left[x^2\right]^4\cdot16=2^{20}\)
\(\Leftrightarrow x^8\cdot16=2^{20}\)
\(\Leftrightarrow x^8\cdot2^4=2^{20}\)
\(\Leftrightarrow x^8=2^{20}:2^4\)
\(\Leftrightarrow x^8=2^{16}\)
\(\Leftrightarrow x^8=\left[2^2\right]^8\)
\(\Leftrightarrow x^8=4^8\Leftrightarrow x=4\)
\(2^{x+3}+2^x=144\)
\(\Leftrightarrow2^x\cdot2^3+2^x=144\)
\(\Leftrightarrow2^x\left[2^3+1\right]=144\)
\(\Leftrightarrow2^x\cdot9=144\)
\(\Leftrightarrow2^x=16\Leftrightarrow x=4\)
Bài cuối tt
X^8=2^16 =>X=4
2^X(2^3+1)=144
=>2^X=16
=>X=4
3^3X(2^2-1)=9^5
=>3^3X=3^9
=>X=3
a) 27 . 32 . 3x+1 = 35 . 81
33 . 32 . 3x+1 = 35 . 34
35 . 3x+1 = 35 . 34
=> 3x+1 = 34
=> x + 1 = 4
x = 4 - 1
x = 3
Vậy x = 3
b) 22 . x + 3 . 23 = 45 . 1000
22 . (x + 3 . 2) = 45 . 1
4 . (x + 6) = 45
x + 6 = 45 : 4
x + 6 = 11,25
x = 11,25 - 6
x = 5,25
Vậy x = 5,25
Ủng hộ mk nha !!! ^_^
a) \(5^x.5^2=3^2+4^2\Leftrightarrow5^x.5^2=25\)
\(\Leftrightarrow5^x=\frac{25}{5^2}=1=5^0\Rightarrow x=0\)
b) \(\left(x-2\right)^3=27\Leftrightarrow\left(x-2\right)^3=3^3\)
\(\Leftrightarrow x-2=3\Leftrightarrow x=5\)
c) \(2018^{x-9}=1\). Ta có: \(2018^0=1\) nên để \(2018^{x-9}=1\) thì \(x-9=0\Leftrightarrow x=9\)
=>3x=32.33
=>3x=35
=>x=5
=>3^x=3^2.3^3
=>3^x=3^5
=>x=5