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\(3^{x+2}+3^x=2430\)
\(\Rightarrow3^x\cdot\left(9+1\right)=2430\)
\(\Rightarrow3^x=2430:10=243\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
ti ck nha
²⁴ʱ๖ۣۜSυρɾεмε...
3^{x+2}+3^x=24303x+2+3x=2430
\Rightarrow3^x\cdot\left(9+1\right)=2430⇒3x⋅(9+1)=2430
\Rightarrow3^x=2430:10=243⇒3x=2430:10=243
\Rightarrow3^x=3^5⇒3x=35
\Rightarrow x=5⇒x=5
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A, (2x+1)3=343
=> (2x+1)3=73
=> 2x + 1 = 7
=> 2x = 6
=> x = 3
B, 2x+2x+3=144
=> 2x+2x . 23 =144
=> 2x ( 1 + 23 ) =144
=> 2x ( 1 + 8 ) =144
=> 2x . 9 =144
=> 2 x = 16
=> 2 x = 2 4
=> x = 4
C, 3x+3x+2=2430
=> 3x+3x . 32 =2430
=> 3x . ( 1 + 32 ) =2430
=> 3x . ( 1 + 9 ) =2430
=> 3x . 10 =2430
=> 3x = 243
=> 3x = 3 5
=> x = 5
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\(2^x+2^{x+1}=48\)
\(2^x.1+2^x.2^1=48\)
\(2^x\left(1+2\right)=48\)
\(2^x.3=48\)
\(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
Vậy x = 4
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a) 3x.3x+2 =81
3x.3x.32 =81
3x.3x.9 =81
3x.3x =81/9
3x.3x =9
31.31 =9
x =1
b)2(x+15)+3(x+25)=2050
2(x+15)+3(x+15+10)=2050
2(x+15)+3(x+15)+3.10=2050
(x+15)(2+5)+30=2050
(x+15)5=2050-30
(x+15)5=2020
x+15=2020/5
x+15=404
x =404-15
x =389
c)2x+2x+1+2x+2+2x+3=960
2x+2x.2+2x.22+2x.23=960
2x(1+2+22+23)=960
2x(1+2+4+8)=960
2x.15=960
2x =960/15
2x =64
26 =64
x =6
bài d làm tương tự c,e làm tương tự a
f)3x.32x+3=729
33x.33=729
33x.27 =729
33x =729/27
33x =27
33.1 =27
x =1
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a) 2x.23 + 2x = 36
=> 2x. (8 + 1) = 36
=> 2x.9 = 36 => 2x = 4 = 22 => x = 2
b) 3x + 3x.32 + 3x.33 = 35.37
=> 3x. (1 + 32 + 33) = 37
=> 3x. 37 = 35.37 => 3x = 35 => x = 5
c) => 52x+ x+2 = 1252.25
=> 53x+2 = (53)2.52 = 58
=> 3x+2 = 8 => 3x = 6 => x = 2
Vậy..
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1) 3^4.2+2^3.5-7(5^7:5^5)
=3^4.2+2^3.5-7.5^2
=81.2+8.5-7.25
=162+40-175
=202-175=27
2) 5.2^2.2^3-4(5^8:5^6)
=5.4.8-3.5^2
=160-100=60
3) (3^5.3^7):3^10+5.2^4-7^3:7
=3^12:3^10+5.16-7^2
=3^2+80-7^2
=9+80-49=40
4) 15:(3^5:3^4)-2^9:2^7
=15:3-2^2
=5-4=1
5) 5.3^5:(3^8:3^5)-2^3.5
=5.3^5:3^3-8.5
=5.3^2-40
=5.9-40
=45-40=5
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3\(^x\) . 3 = 43
=> 3\(^{\left(x+1\right)}\) = 43
=> Không có giá trị x thoả mãn .
49 . \(7^x\) = 2041
7\(^2\) . 7\(^x\) = 2041
7\(^{\left(x+2\right)}\) = 2041
=> \(7^{\left(x+2\right)}\) = 7\(^4\)
=> x + 2 = 4
=> x = 2
\(3^x\)\(x3^2\)\(+3^x\)\(x1=2430\)
\(3^x\)\(x9+3^x\)\(x1=2430\)
\(3^x\)\(\left(9+1\right)=2430\)
\(3^x\)\(x10=2430\)
\(3^x\)\(=2430:10=243=3^5\)
\(3^x\)\(=3^5\)
\(=>x=5\)