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a = (7^2.2^3+6^2.2^3+2.5.2^4-40) : 8
= (7^2.8+6^2.8+2^2.5.8-5.8) : 8
= 7^2+6^2+2^2.5-5 = 49+36+20-5 = 100
k mk nha
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\(3^2.5+2^3.10-3^4:3\)
\(=5\left(3^2+2^3.2\right)-3^{4-1}\)
\(=5\left(9+16\right)-3^3\)
\(=5.25-27\)
\(=125-27=98\)
\(3^2\times5+2^3\times10-3^4:3\\ =9\times5+8\times10-27\\ =45+80-27\\ =98.\)
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Lời giải:
\(\frac{2}{5}\times \frac{10}{7}\times \frac{-3}{4}\times \frac{10}{7}+\frac{5}{2}:2=\frac{-30}{49}+\frac{5}{4}=\frac{125}{196}\)
Em nên gõ công thức trực quan để đề bài được rõ ràng nhé
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\(a.\frac{19}{13}+\frac{-7}{11}+\frac{-4}{11}-\frac{6}{13}\)
\(=\left(\frac{19}{13}-\frac{6}{13}\right)+\left(\frac{-7}{11}+\frac{-4}{11}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
\(3.10^3+2.10^2+5.10\)
\(=10.\left(3.10^2+2.10+5\right)\)
\(=10.\left(3.100+20+5\right)\)
\(=10.325\)
\(=3250\)