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Trả lời:
\(\left(3x-2^4\right)\times7^3=2\times7^3\)
\(\Leftrightarrow3x-16=2\)
\(\Leftrightarrow3x=18\)
\(\Leftrightarrow x=6\)
Vậy \(x=6\)
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c)
\(4\left(3x-4\right)-2=18\)
<=> \(12x-16-2=18\)
<=> \(12x=36\)
<=> \(x=3\)
Vậy x=3
d)
\(\left(3x-10\right):10=50\)
<=> \(3x-10=500\)
<=> \(3x=510\)
<=> x= \(170\)
Vậy x= 170
f)
\(x-\left[42+\left(-25\right)\right]=-8\)
<=> \(x-17=-8\)
<=> x= \(9\)
Vậy x=9
h)
\(x+5=20-\left(12-7\right)\)
<=> \(x+5=15\)
<=> \(x=10\)
Vậy x= 10
k)
\(\left|x-5\right|=7-\left(-3\right)\)
<=> \(\left|x-5\right|=10\)
* Với \(x>=5\) ; ta được:
\(x-5=10\)
<=> x= 15 (thoả mãn điều kiện )
*Với \(x< 5\) ; ta được:
\(-\left(x-5\right)=10\)
<=> \(-x+5=10\)
<=> \(-x=5\)
<=> \(x=-5\) (thoả mãn điều kiện)
Vậy x=15 ; x= -5
i)
\(\left|x-5\right|=\left|7\right|\)
<=> \(\left|x-5\right|=7\)
*Với \(x>=5\) ; ta được:
\(x-5=7\)
<=> \(x=12\) (thoả mãn)
*Với \(x< 5\) ; ta được:
\(-\left(x-5\right)=7\)
<=> \(-x=2\)
<=> \(x=-2\) (thoả mãn)
Vậy x= 12; x= -2
m)
\(2^{x+1}.2^{2009}=2^{2010}\)
<=> \(2^{x+1+2009}=2^{2010}\)
<=> \(2^{x+2010}=2^{2010}\)
=> \(x+2010=2010\)
=> \(x=0\)
Vậy x=0
n)
\(10-2x=25-3x\)
<=>\(x=15\)
Vậy x=15
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75.(3x - 23) = 74.72
=> 75.(3x - 8) = 76
=> 3x - 8 = 7
=> 3x = 15
=> x = 5
Vậy x = 5
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(3x-24).73=2.74
=>3x-24=2.74:73
=>3x-16=2.7
=>3x-16=14
=>3x=16+14
=>3x=30
=>x=10
Vậy x=10
\(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-16\right).343=4802\)
\(\left(3x-16\right)=4802:343\)
\(\left(3x-16\right)=14\)
\(3x-16=14\)
\(3x=16+14\)
\(3x=30\)
\(x=30:3=10\)
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a) 71 + \(\frac{26-3x}{5}=75\)
↔ \(\frac{26-3x}{5}=4\)
↔\(26-3x=20\)
↔x=2
b) \(x-17=\left(-8\right)-17\)
↔ \(x-17=-25\)
↔\(x=-8\)
c)\(\left(5x-2\right).6^3=3.6^5\)
↔\(\left(5x-2\right)=3.6^2\)
↔\(5x=110\)
↔\(x=22\)
d)\(\left(3x-2^4\right).7^3=2.7^4\)
↔\(3x-16=14\)
↔x=10
tick nha~~
( 3x - 24) . 73 = 2 . 73
( 3x - 24) . 73 = 2 . 343
(3x - 24) . 343 = 686
3x - 24 = 686 : 343
3x - 16 = 2
3x = 2 + 16
3x = 18
x = 18 : 3
x = 6