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\(3\sqrt{50}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}+2\sqrt{28}\)
\(=15\sqrt{2}-14\sqrt{2}-15\sqrt{2}-3\sqrt{7}+4\sqrt{7}\)
\(=-14\sqrt{2}-3\sqrt{7}+4\sqrt{7}\)
\(=-14\sqrt{2}+\sqrt{7}\)
a) \(3\sqrt{8}-4\sqrt{18}+5\sqrt{32}-\sqrt{50}=3\sqrt{4.2}-4\sqrt{9.2}+5\sqrt{16.2}-\sqrt{25.2}=6\sqrt{2}-12\sqrt{2}+20\sqrt{2}-5\sqrt{2}=9\sqrt{2}\)b) \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):10=\left(15\sqrt{50}+5\sqrt{50.4}-3\sqrt{50.9}\right):10=\left(15\sqrt{50}+10\sqrt{50}-9\sqrt{50}\right):10=\dfrac{16\sqrt{50}}{10}=\dfrac{16\sqrt{25.2}}{10}=\dfrac{80\sqrt{2}}{10}=8\sqrt{2}\) c) \(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}=2\sqrt{7.4}+2\sqrt{7.9}-3\sqrt{7.25}+\sqrt{7.16}=4\sqrt{7}+6\sqrt{7}-15\sqrt{7}+4\sqrt{7}=-\sqrt{7}\)
d)
\(\left(\sqrt{14}-3\sqrt{2}\right)^2+6\sqrt{28}=14-2.3\sqrt{2.14}+18+6\sqrt{28}=32-6\sqrt{28}+6\sqrt{28}=32\)
b: \(\Leftrightarrow\sqrt{25x-75}=x+3\)
=>25x-75=x^2+6x+9 và x>=-3
=>x^2+6x+9-25x+75=0 và x>=-3
=>x^2-19x+84=0 và x>=-3
=>\(x\in\varnothing\)
c: \(\Leftrightarrow x+1+4\cdot3x+4\sqrt{3x\left(x+1\right)}=64\)
=>\(4\sqrt{3x\left(x+1\right)}=64-12x-x-1=-13x+63\)
=>\(48x\left(x+1\right)=\left(-13x+63\right)^2\)
=>\(48x^2+48x=169x^2-1638x+3969\)
=>x=1323/121 hoặc x=3
\(a.6\sqrt{3}-2\sqrt{12}+5\sqrt{300}-7\sqrt{243}=6\sqrt{3}-4\sqrt{3}+50\sqrt{3}-63\sqrt{3}=\left(6-4+50-63\right)\sqrt{3}=-11\sqrt{3}\)
\(b.\sqrt{28}+3\sqrt{63}-6\sqrt{175}-\dfrac{1}{5}\sqrt{252}=2\sqrt{7}+9\sqrt{7}-30\sqrt{7}-\dfrac{6}{5}\sqrt{7}=\left(2+9-30-\dfrac{6}{5}\right)\sqrt{7}=-20,2\sqrt{7}\)\(c.5\sqrt{44}-2\sqrt{275}-3\sqrt{176}=10\sqrt{11}-10\sqrt{11}-12\sqrt{11}=-12\sqrt{11}\)
\(d.2\sqrt{75}-\sqrt{12}+2\sqrt{147}-7\sqrt{103}=10\sqrt{3}-2\sqrt{3}+14\sqrt{3}-7\sqrt{103}=22\sqrt{3}-7\sqrt{103}\)
\(a.6\sqrt{3}-2\sqrt{12}+5\sqrt{300}-7\sqrt{243}=6\sqrt{3}-4\sqrt{3}+50\sqrt{3}-63\sqrt{3}=-11\sqrt{3}\)
\(b.\sqrt{28}+3\sqrt{63}-6\sqrt{175}-\dfrac{1}{5}\sqrt{252}=2\sqrt{7}+9\sqrt{7}-30\sqrt{7}-\dfrac{6}{5}\sqrt{7}=-\dfrac{101}{5}\sqrt{7}\)
\(c.5\sqrt{44}-2\sqrt{275}-3\sqrt{176}=20\sqrt{11}-10\sqrt{11}-12\sqrt{11}=-2\sqrt{11}\)
\(d.2\sqrt{75}-\sqrt{12}+2\sqrt{147}-7\sqrt{103}=10\sqrt{3}-2\sqrt{3}+14\sqrt{3}-7\sqrt{103}=22\sqrt{3}-7\sqrt{103}\)
3 căn 56 nha
\(3\sqrt{56}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}+2\sqrt{28}=3\sqrt{4.14}-2\sqrt{49.2}-5\sqrt{9.2}-\sqrt{9.7}+2\sqrt{4.7}=3.2\sqrt{14}-2.7\sqrt{2}-5.3\sqrt{2}-3\sqrt{7}+2.2\sqrt{7}=6\sqrt{14}-14\sqrt{2}-15\sqrt{2}-3\sqrt{7}+4\sqrt{7}=6\sqrt{14}-29\sqrt{2}+\sqrt{7}\)