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\(5.3^{x+1}-4.3^{x-2}=393\)
\(5.3^x.3-4.3^x:9=393\)
\(3^x\left(15-\frac{4}{9}\right)=393\)
\(3^x\frac{131}{9}=393\)
\(3^x=27\)
\(3^x=3^3\)
\(\Rightarrow x=3\)
393-(126+3X)=0
126+3X. =393-0
126+3X =393
3X =393-126
3X =267
X. =267 : 3
X. =89
Còn câu dưới hình như đề sai
393-19.(x-7)=169:13
=> 393-19.(x-7)=13
=> 19(x-7)=393-13
=> 19(x-7)=380
=> x-7=380:19
=> x-7=20
=> x= 20+7
=> x=27
Vậy x = 27
1+3-5-7+9+11-13-...+393+395-397-399+401
= 1+3-5-7+9+11-13-...+393+395-397-399+401-401
= 1+(3-5-7+9) +...+ (395-397-399+401) -401
= 1+0+0+0+...+0 - 401
=1 - 401
= - 401
C1: Áp dụng khi \(\dfrac{a}{b}>1\) thì \(\dfrac{a}{b}>\dfrac{a+m}{b+m}\left(m\in N^{\circledast}\right)\)
Ta thấy \(\dfrac{20^{2015}-1}{20^{2015}-3}>1\)
\(\Rightarrow B=\dfrac{20^{2015}-1}{20^{2015}-3}>\dfrac{20^{2015}-1+2}{20^{2015}-3+2}=\dfrac{20^{2015}+1}{20^{2015}-1}=A\)
Vậy \(B>A\)
a)17.85+15.17−120a)17.85+15.17-120
⇔1445+15.17−120⇔1445+15.17−120
⇔1445+255−120⇔1445+255−120
⇔1580⇔1580
b)2³.17−2³.14b)2³.17-2³.14
⇔8.17−8.14⇔8.17−8.14 ⇔136−8.14⇔136−8.14
⇔24⇔24 c)20−[30−(5−1)²:2]c)20-[30-(5-1)²:2]
⇔20−(30−42:2)⇔20−(30−42:2)
⇔20−(30−8)⇔20−(30−8)
⇔−2⇔-2
d)80−(4.5²−3.2²)d)80-(4.5²-3.2²)
⇔80−(4.25−3.22)⇔80−(4.25−3.22)
⇔80−(100−12)⇔80−(100−12)
⇔−8⇔-8
e) 27.77+24.27−2727.77+24.27-27
⇔ 27.77+24.27−27.1⇔ 27.77+24.27-27.1
⇔27.(77+24−1)⇔27.(77+24-1)
⇔27⇔27
g)174:{2.[36+(4²−23)]}g)174:{2.[36+(4²-23)]}
⇔ 174:{2⋅[36+(16−23)]}⇔ 174:{2⋅[36+(16−23)]}
⇔174:{2⋅[36−7]}⇔174:{2⋅[36−7]}
⇔ 174:{2⋅29}⇔ 174:{2⋅29}
⇔ 174:58⇔ 174:58
⇔ 3
393+2=395
395 k mk 3 k mk k lại thề lun