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A) \(\frac{7^{2003}+7^{2002}}{7^{2004}}=\frac{7^{2003}}{7^{2004}}+\frac{7^{2002}}{7^{2004}}=\frac{1}{7}+\frac{1}{7^2}=\frac{8}{49}\)
B) Xem lại đề bài
390 - (x-7 ) - 169 : 13 = 0
390 - (x-7 ) - 13 = 0
390 - (x-7) = 13 +0
390 -(x-7 ) = 13
x-7 = 390 -13
x-7 = 377
x= 377 +7
x= 384
390-(x-7)-169:13=0
390-(x-7)-13=0
390-(x-7)=0+13
390-(x-7)=13
x-7=390-13
x-7=377
x=377+7
x=384
vậy x=384
\(325-3.\left(x-7\right)=169:13\)
\(325-3.\left(x-7\right)=13\)
\(3.\left(x-7\right)=325-13\)
\(3.\left(x-7\right)=312\)
\(x-7=312:3\)
\(x-7=104\)
\(x=104+7\Rightarrow x=111\)
390 - ( x - 7 ) = 169 : 13
390 - ( x - 7 ) = 13
x - 7 = 390 - 13
x - 7 = 377
x = 377 + 7
x = 384
\(390-\left(x-7\right)=169:13\)
\(390-\left(x-7\right)=13\)
\(x-7=390-13\)
\(x-7=377\)
\(x=377+7\)
\(x=384\)
k nha
a) 390 - (x - 7) = 169 : 13
390 - (x - 7) = 13
x - 7 = 390 - 13
x - 7 = 377
x = 377 + 7
x = 384
b) ( x - 140 ) : 7 = 32 - 23 . 3
(x - 140) : 7 = -15
x - 140 = -15 . 7
x - 140 = -105
x = 105 + 140
x = 35
a) 390 - (x - 7) = 169 : 13
390 - (x - 7) = 13
x - 7 = 390 - 13 = 377
x = 377 + 7
x = 384
a)390-(x-7)=169:13
<=>390-(x-7)=13
<=>x-7=390-13
<=>x-7=377
<=>x=377+7
<=>x=384
b)x-6:2-(48-24):2:6-3=0
<=>x-3-24:2:6-3=0
<=>x-6-12:6=0
<=>x-6-2=0
<=>x-8=0
<=>x=8
a) 390 - ( x - 7 ) = 169 : 13
390 - ( x - 7 ) = 13
x - 7 = 390 - 13
x - 7 = 377
x = 377 + 7
x = 384
b) x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0
x - 3 - ( 48 - 24 ) : 2 : 6 = 0 + 3 = 3
x - 3 - ( 48 - 24 ) : 2 = 3 x 6 = 18
x - 3 - ( 48 - 24 ) = 18 x 2
x - 3 - 24 = 36
x - 3 = 36 + 24
x - 3 = 60
x = 60 + 3
x = 63
a) (54 + 57) . (89 - 27) . (24 - 42)
= (54 + 57) . (89 - 27) . (16 - 16)
= (54 + 57) . (89 - 27) . 0
= 0
b) (72003 + 72002) : 72001
= 72003 : 72001 + 72002 : 72001
= 72 + 7
= 49 + 7
= 53
c) (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 132)
= (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 169)
= (169 - 42 ) × ( 169 - 52 ) ×......× 0
= 0
Tìm x biết
7 × ( x - 14 ) + 39 = 25 + 279 ÷ 9
=> 7 × ( x - 14 ) + 39 = 25 + 31
=> 7 × ( x - 14 ) + 39 = 56
=> 7 × (x - 14) = 56 - 39
=> 7 × (x - 14) = 17
=> x - 14 = 17 : 7
=> x - 14 = 17/7
=> x = 17/7 + 14
=> x = 115/7
\((5^4+4^7)\times(8^9-2^7)\times(2^4-4^2)\)
\(=(5^4+4^7)\times(8^9-2^7)\times0\)
\(=0\)
A=\(\frac{6}{19}\). \(\frac{-7}{11}\)+\(\frac{6}{19}\).\(\frac{-4}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).(\(\frac{-7}{11}\)+\(\frac{-4}{11}\))+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).\(\frac{-11}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).-1 +\(\frac{-13}{19}\)
=\(\frac{-6}{19}\)+\(\frac{-13}{19}\)
=\(\frac{-19}{19}\)
+1
393-19.(x-7)=169:13
=> 393-19.(x-7)=13
=> 19(x-7)=393-13
=> 19(x-7)=380
=> x-7=380:19
=> x-7=20
=> x= 20+7
=> x=27
Vậy x = 27
393-19.(x-7)=169:13
= 393-19.(x-7)=13
= 19.(x-7)=393-13
= 19.(x-7)=380
= x-7 =380:19
= x-7= 20
= x = 20+7
= x = 27