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=> x . ( 2 + 3 + 4 + 5 + 6 ) = x . 9 + 9999
=> x . 20 = x . 9 + 9999
=> x . 11 = 9999 ( cùng bớt x + 9 )
=> x = 9999 : 11
=> 909
2x + 3x + 4x + 20x + 6x = 9x + 9999
35x - 9x = 9999
26x = 9999
x = 9999 / 26
Vậy : x = 9999 / 26
6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001
1 / 5 + x = 3 / 7 + 1 / 3
1 / 5 + x = 16 /21
x = 16 / 21 - 1 / 5
x = 59 / 105
x - 1 / 2 = 2 / 3 - 1 / 5
x - 1 / 2 = 7 / 15
x = 7 / 15 + 1 / 2
x = 29 / 30
3 / 5 * x = 2 / 7+ 1 / 4
3 / 5 * x = 15 / 28
x = 15 / 28 : 3 / 5
x = 25 / 28
7 / 8 : x = 1 / 6 * 2 / 3
7 / 8 : x = 1 / 9
x = 7 / 8 : 1 / 9
x = 63 / 8
khỏi chép đề nha
a\Câu 1:
200 : ( 15 - x ) = 15 + 5
200 : ( 15 - x ) = 20
15 - x = 200 : 20
15 - x = 10
x = 15 - 10
x = 5
Câu 2:
63 : ( x - 5 ) = 22 -1
63 : ( x - 5 ) = 21
x - 5 = 63 : 21
x - 5 = 3
x = 3 + 5
x = 8
\(3\left(x-\dfrac{1}{6}\right)-2\left(x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy \(x=\dfrac{1}{2}\)
\(\frac{1}{3}x=\frac{1}{6}\Leftrightarrow x=\frac{1}{6}:\frac{1}{3}=\frac{1}{2}\)
\(\frac{3}{4}:x=\frac{1}{2}\Leftrightarrow\frac{3}{4x}=\frac{1}{2}\Leftrightarrow4x=3:\frac{1}{2}\Leftrightarrow4x=6\Leftrightarrow x=\frac{6}{4}=\frac{3}{2}\)
Ai đang online giải giúp mik nha:
A=1+8+27+64+125+216+343+512+729+1000
\(x\times6+x:3=\frac{1}{2}\)
=> \(x\times6+x\times\frac{1}{3}=\frac{1}{2}\)
=> \(x\times\left(6+\frac{1}{3}\right)=\frac{1}{2}\)
=> \(x\times\frac{19}{3}=\frac{1}{2}\)
=> x = 1/2 : 19/3
=> x = 3/38
Vậy ...
\(x\times6+x\div3=\frac{1}{2}\)
\(\Leftrightarrow6x+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow6x\times1+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow6x\times\frac{3}{3}+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow\frac{6x}{1}\times\frac{3}{3}+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow\frac{6x\times3}{1\times3}+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow\frac{18x}{3}+\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow\frac{18x+x}{3}=\frac{1}{2}\)
\(\Leftrightarrow\frac{19x}{3}=\frac{1}{2}\)
\(\Leftrightarrow19x\times2=3\times1\)
\(\Leftrightarrow38x=3\)
\(\Leftrightarrow x=\frac{3}{38}\)
\(\dfrac{3}{6}\times x=\dfrac{3}{2}\)
\(\dfrac{1}{2}\times x=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}:\dfrac{1}{2}\)
\(x=\dfrac{3}{2}\times2\)
\(x=3\)
3/6 x x=3/2
x=3/2:3/6
x=3