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a: \(A=\left(41.54+8.46\right)-\left(3.18+5.82\right)+\left(23.17-3.17\right)\)
=50-9+20
=70-9
=61
b: \(B=123.8-\left(34.15+5.84\right)+\left(-12.49+2.49\right)\)
\(=123.8-40-10=73.8\)
c: \(C=\left(32.18-2.18\right)+\left(36.42-6.42\right)+\left(13.93-3.93\right)\)
=30+30+10
=70
a: A=(41.54+8.46)−(3.18+5.82)+(23.17−3.17)A=(41.54+8.46)−(3.18+5.82)+(23.17−3.17)
=50-9+20
=70-9
=61
b: B=123.8−(34.15+5.84)+(−12.49+2.49)B=123.8−(34.15+5.84)+(−12.49+2.49)
=123.8−40−10=73.8=123.8−40−10=73.8
c: C=(32.18−2.18)+(36.42−6.42)+(13.93−3.93)C=(32.18−2.18)+(36.42−6.42)+(13.93−3.93)
=30+30+10
=70
a: \(=41.54+8.46-3.18-5.82+23.17-3.17\)
=50-9+20
=70-9=61
b: \(=123.8-34.15-5.85-12.49+2.49+10\)
=123,8-40
=83,8
c: \(=32.18+36.42+13.93-2.18-6.42-3.93\)
=30+30+10
=70
\(\frac{9}{22}x55=\frac{9x55}{22}=\frac{495}{22}\frac{45}{2}\)
k mình nhé các bạn
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
\(\frac{9}{22}\times\frac{33}{18}\)
\(=\frac{9\times33}{22\times18}\)
\(=\frac{297}{396}\)
\(=\frac{3}{4}\)
1,1 + 2,2 + 3,3 +.. + 29,9 + 22 = 11. ( 0,1 + 0,2 + 0,3 + ... + 1,9 + 2 ) = 11 . 21 = 231
22 - 1,1 + 1 = 20
22 + 1,1 = 23,1
23,1 / 2 = 11,55
11,55 * 20 = 231
\(\frac{34}{11}\cdot\frac{1269}{46}\cdot\frac{23}{17}\cdot\frac{22}{9}\)
\(=\frac{34\cdot1269\cdot23\cdot22}{11\cdot46\cdot17\cdot9}\)
\(=\frac{17\cdot2\cdot141\cdot9\cdot23\cdot11\cdot2}{11\cdot23\cdot2\cdot17\cdot9}\)
\(=\frac{2\cdot141\cdot2}{2}\)
\(=141\cdot2\)
\(=282\)
333,56+3,93-22+9= 324,49 nha