Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Mủ => mũ nha bạn. À câu trên bạn sai rồi. Sửa nè
Ta có : \(A=280:\left\{5^2+\left[240:8-\left(5-2\right)^3\right]\right\}\)
\(=280:\left\{25+\left[30-3^3\right]\right\}\)
\(=280:\left\{25+\left[30-27\right]\right\}\)
Rồi đến đó bạn tiếp tục làm nha!
240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
|
x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
(-12).32+240:(-2)2=(-12).9+240:4=(-108)+60= -48
1) \(\left(+15\right)+\left(+17\right)=15+17=32\)
2) \(\left(-3\right)+\left(-7\right)=-3-7=-\left(3+7\right)=-10\)
3) \(\left(-25\right)+\left(+4\right)=-25+4=-\left(25-4\right)=-21\)
4) \(\left(-6\right)+\left(-54\right)=-6-54=-\left(6+54\right)=-60\)
5) \(\left(-15\right)+20=20-15=5\)
6) \(\left(-5\right)+8+7+5\)
\(=\left(-5+5\right)+\left(8+7\right)\)
\(=15\)
7) \(\left(-8\right)+\left(-11\right)+\left(-2\right)\)
\(=\left[\left(-8\right)+\left(-2\right)\right]+\left(-11\right)\)
\(=\left(-10\right)+\left(-11\right)\)
\(=-21\)
8) \(15+\left(-5\right)+\left(-14\right)+\left(-16\right)\)
\(=\left[15+\left(-5\right)\right]+\left[\left(-14\right)+\left(-16\right)\right]\)
\(=10+\left(-30\right)\)
\(=-20\)
9) \(\left(-20\right)+\left(-14\right)+3+\left(-86\right)\)
\(=\left[\left(-20\right)+3\right]+\left[\left(-14\right)+\left(-86\right)\right]\)
\(=\left(-17\right)+\left(-100\right)\)
\(=-117\)
10) \(\left(-136\right)+123+\left(-264\right)+\left(-83\right)+240\)
\(=\left[\left(-136\right)+\left(-264\right)\right]+\left[123+\left(-83\right)\right]+240\)
\(=\left(-400\right)+40+240\)
\(=\left(-360\right)+240\)
\(=-120\)
11) \(\left(-596\right)+2001+1999+\left(-404+189\right)\)
\(=\left(-596\right)+2001+1999-404+189\)
\(=\left[\left(-596\right)-404\right]+\left(2001+189\right)+1999\)
\(=\left(-1000\right)+2190+1999\)
\(=1190+1999\)
\(=3189\)
12) \(314+\left(-153\right)+64+121+\left(-247\right)+218\)
\(=\left(314+64+121\right)+\left[\left(-153\right)+\left(-247\right)\right]+218\)
\(=\left(378+121\right)+\left(-400\right)+218\)
\(=499-400+218\)
\(=99+218\)
\(=317\)
\(\text{#}Toru\)
Trả lời:
(-65)-(-37)
= (-65)+37
=-28
(-159)-280:(-7)
=(-159)-(-40)
=(-159)+40
=-119
(-12).\(3^2\)+240:\(\left(-2\right)^2\)
=-108+60
=-48
\(5.\left(-2\right)^3-36:3^2\)
=\(-40-4\)
=\(-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]:\left(-4\right)\)
=\(128-\left[68+8.4\right]:\left(-4\right)\)
=\(128-\left[68+32\right]:\left(-4\right)\)
=\(128-100:\left(-4\right)\)
=\(128-\left(-25\right)\)
=\(153\)
\(-141+3^3+\left(-2\right)^2\)
=\(-141+9+4\)
=\(-132+4\)
=\(-128\)
chúc bạN HOK TỐT
1)(-65)-(-37)=-28
2)(-159)-280:(-7)
=(-159)-(-40)
=-119
3)(-12).3\(^2\)+240:(-2)\(^{^2}\)
=-108+60
=-48
4)5.(-2)\(^3\)-36:3\(^2\)
=-40-4
=-44
5) 128-[68+8.(35-37)2]:(-4)
=128-[68+8.-2\(^2\)]:(-4)
=128-[68+32]:(-4)
=128-100:(-4)
=128-(-25)
=153
6)-141+3\(^3\)+(-2)\(^2\)
=-114+4
=-110
\(\left(-65\right)-\left(-37\right)=\left(-65\right)+37=-\left(65-37\right)=-28\)
\(\left(-159\right)-280\div\left(-7\right)=\left(-159\right)-\left(-40\right)=-119\)
\(\left(-12\right).3^2+240\div\left(-2\right)^2=\left(-12\right).9+240\div4=\left(-108\right)+60=-48\)
\(5.\left(-2\right)^3-36\div3^2=5.\left(-8\right)-36\div9=\left(-40\right)-4=-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]\div\left(-4\right)=128-\left[69+8\left(-2\right)^2\right]\div4\)
\(=128-\left(69+8.4\right)\div4=128-101\div4=128-25,25=102,75\)
\(\left(-141\right)+3^3+\left(-2\right)^2=\left(-141\right)+27+4=\left(-141\right)+31=-110\)
240 : 3 : 8 - (x - 50) : 3 = 6
<=> 10 - (x - 50) : 3 = 6
<=> - (x - 50) : 3 = -4
<=> - x + 50 = -12
<=> - x = -62
<=> x = 62
a) \(\frac{y}{6}=\frac{2010}{15}\) c) \(x-\frac{1}{3}=\frac{1}{4}\) e)\(5y-1952=2500-1947\)
\(y=\frac{2010}{15}.6\) \(x=\frac{1}{4}+\frac{1}{3}\) \(5y-1952=553\)
\(y=804\) \(x=\frac{7}{12}\) \(5y=553+1952\)
\(5y=2505\)
\(y=2505:5=501\)
b) \(x+\frac{1}{2}=\frac{3}{4}\) c) \(3x+\frac{3}{8}=\frac{1}{2}\)
\(x=\frac{3}{4}-\frac{1}{2}\) \(3x=\frac{1}{2}-\frac{3}{8}\)
\(x=\frac{1}{4}\) \(3x=\frac{1}{8}\)
\(x=\frac{1}{8}:3\)
\(x=\frac{1}{24}\)
f)\(\left(8y-1942\right).1947=\left(240-194,2\right).19470\)
\(\left(8y-1942\right).1947=45,8.19470\)
\(\left(8y-1942\right)=45,8.19470:1947\)
\(8y-1942=45,8.10\)
\(8y-1942=458\)
\(8y=458+1942\)
\(8y=2400\)
\(y=2400:8\)
\(y=300\)
úm bala alaba trap
đặt A=3+3^2+..+3^8
=3(1+3+..+3^7)
\(=3\left[\left(1+3+3^2+3^3\right)+3^4\left(1+3+3^2+3\right)\right]\\ =3\left(40+3^4.40\right)=120.\left(3^4+1\right)\)
do 3^4 chia hết cho 2 nên A chia hết cho 240