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1 m2 = 100 dm2 = 10000 cm2
1 km2 = 100 ha = 1000000 m2
1 ha = 1 hm2 = 0,01 km2
1m2 = .100..............dm2 = .....10000............cm2
1km2 = .100..........ha = ..1000000........m2
1ha = ......1...........hm2 = ...0,01..............km2
![](https://rs.olm.vn/images/avt/0.png?1311)
So so hang cua G la (100-1)+1=100
tong G la (1+100).100:2=5050
co phai ghi 10 la 100 phai khong ban neu dung k nha
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ta có chiều cao của thửa ruộng hình thang là :
\(360\times\frac{2}{48}=15m\)
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Bài làm:
Ta có: \(\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}.2^{26}}\)
\(=\frac{7.2^{10}.3^{10}.2^{20}.3^6-2^{19}.2^{15}.3^{15}}{3^2.2^{19}.3^{19}.2^9-2^2.3^{17}.2^{26}}\)
\(=\frac{2^{30}.3^{16}.7-2^{34}.3^{15}}{2^{28}.3^{21}-2^{28}.3^{17}}\)
\(=\frac{2^{30}.3^{15}\left(3.7-2^4\right)}{2^{28}.3^{17}\left(3^4-1\right)}\)
\(=\frac{2^2\left(21-16\right)}{3^2\left(81-1\right)}\)
\(=\frac{2^2.5}{3^2.80}\)
\(=\frac{1}{36}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(\frac{38}{11}+\frac{4}{17}-\frac{5}{11}-\frac{3}{17}\)
\(=\frac{38}{11}-\frac{5}{11}+\frac{4}{17}-\frac{3}{17}\)
\(=\frac{33}{11}+\frac{1}{17}\)
\(=3+\frac{1}{17}\)
\(=\frac{52}{17}\)
38/11+4/17-5/11-3/17
=(38/11-5/11)+(4/17-3/17)
=3+1/17
=51/17+1/17=52/17
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mik sửa lại một tí nha
1 : 0,125 + 1 : 0,1
0,18 x 1230 + 0,9 x 4567 x 2 + 3 x 5310 x 0,6
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Y*25%+y*3/4*y=20
=>y*(25%+3/4)*y=20
=>y*y=20 =>y=4,472135954999579(đề sai hay sao ấy)