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5x = 625
=> 5x = 54
=> x = 4
3 . 2x = 96
=> 2x = 96 : 3
=> 2x = 32
=> 2x = 25
=> x = 5
c) 8x + 1 = 165
=> (23)x + 1 = (24)5
=> 23(x + 1) = 24.5
=> 23(x + 1) = 220
=> 3(x + 1) = 20
=> x + 1 = 20:3
=> x + 1 = 20/3
=> x = 20/3 - 1
=> x = 17/3
1) 5x = 625
<=. 5x = 54
<=> x = 4
=> x = 4
2) 3.2x = 96
<=> 2x = 96 : 3
<=> 2x = 32
<=> 2x = 25
<=> x = 5
=> x = 5
3) 8x + 1 = 165
<=> (23)x + 1 = (24)5
<=> 23.(x + 1) = 24.5
<=> 3.(x + 1) = 4.5
<=> 3.(x + 1) = 20
<=> x + 1 = 20 : 3
<=> x + 1 = 20/3
<=> x = 20/3 - 1
<=> x = 17/3
=> x = 17/3


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\(10+2\cdot x=4^5:4^3\)
\(\Rightarrow10+2\cdot x=4^{5-3}\)
\(\Rightarrow10+2\cdot x=4^2\)
\(\Rightarrow10+2\cdot x=16\)
\(\Rightarrow2\cdot x=16-10\)
\(\Rightarrow2\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
__________________
\(2\cdot x-6^2:18=3\cdot2^2\)
\(\Rightarrow2\cdot x-36:18=12\)
\(\Rightarrow2\cdot x-2=12\)
\(\Rightarrow2\cdot x=12+2\)
\(\Rightarrow2\cdot x=14\)
\(\Rightarrow x=\dfrac{14}{2}=7\)
_________________
\(70-5\cdot\left(x-3\right)=3\cdot2\)
\(\Rightarrow70-5\cdot\left(x-3\right)=6\)
\(\Rightarrow70-5x+15=6\)
\(\Rightarrow-5x+15=6-70\)
\(\Rightarrow-5x+15=64\)
\(\Rightarrow-5x=64-15\)
\(\Rightarrow-5x=49\)
\(\Rightarrow x=-\dfrac{49}{5}\)

1) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)
\(-\frac{2}{3}x+\frac{1}{6}=\frac{2}{3}x-\frac{1}{3}\)
\(-\frac{2}{3}x-\frac{2}{3}x=-\frac{1}{3}-\frac{1}{6}\)
\(-\frac{4}{3}x=-\frac{1}{2}\)
\(x=\left(-\frac{1}{2}\right):\left(-\frac{4}{3}\right)\)
\(x=\frac{3}{8}\)

2/ 3.2.x +3/5.x = 6.x+3/5.x =(6+3/5).x =33/5.x
\(\frac{2}{3.2.x}+\frac{3}{5.x}\)
\(=\frac{1}{3x}+\frac{3}{5x}\)
\(=\frac{5x+9x}{15x^2}=\frac{14x}{15x^2}=\frac{14}{15x}\)
3 . 2x = 96
2x = 96 : 3
2x = 32
2x = 25
⇒ x = 5
Vậy x = 5
`3.2^x= 96`
`2^x = 96 : 3`
`2^x = 32`
`2^x = 2^5`
`=> x = 5`